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3 years ago

Why do you see objects when you shine a flashlight in a dark room?

Physics

1 answer:

anzhelika [568]3 years ago

8 0

Explanation:

We see objects in a dark room due to the emission of light photons which are sensitive to our eyes.

Darkness is simply a terminology used to describe the absence of light. Visible light to human is a component of the electromagnetic spectrum. Our eyes have receptors that picks the photons which light releases.

The particles of light are called photons.

When a torch is shines. It produces light due to emission of light by excitation of the metal in the bulb.
The light is in form of photons that spreads and travels in all direction in a room.
When they impinge on other bodies, they cause them to excite and release their own photons
Photons from the different parts helps to depict an object as it is.
The photo-receptors in our eyes picks up the photon and interprets it in our visual faculty.

learn more:

light waves brainly.com/question/8032392

#learnwithBrainly

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A 2-kg object is moving 6 m/s in a horizontal direction.

german

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

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2 years ago

A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the

Alexxandr [17]

Answer: $3.5\ km$

Explanation:

Given

Car starts from the state of rest and acquires a velocity of $70\ km/hr$ in 6 minutes

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Using equation of motion

$v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2$

Distance covered in 360 s

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2 years ago

A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60

mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

Also, the east bound travels as a function of time and can be given as:

y(t) = 60t

Now,

To calculate the speed, z(t) of the train as it passes through the intersection:

Since, the road cross at right angles, thus by Pythagoras theorem:

$z(t) = \sqrt{x^{2} + y(t)^{2}}$

$z(t) = \sqrt{70^{2} + 60t^{2}}$

Now, differentiate the above eqn w.r.t 't':

$\frac{dz(t)}{dt} = \frac{1}{2}.\frac{1}{sqrt{3600t^{2} + 4900}}\times 2t\times 3600$

$\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t$

For t = 4 s:

$\frac{dz(4)}{dt} = \frac{1}{sqrt{3600\times 4^{2} + 4900}}\times 3600\times 4 = 57.6\ m/s$

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2 years ago

When a guitar string is plucked, in what direction does the wave travel? In what directions does the string vibrate?

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Answer: the waves travel in an horizontal direction while the strings vibrate in a vertical direction.

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2 years ago

Read 2 more answers

A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo

zloy xaker [14]

Solution :

Given :

Mass attached to the spring = 4 kg

Mass dropped = 6 kg

Force constant = 100 N/m

Initial amplitude = 2 m

Therefore,

a). $v_{initial} = A w$

$= 2 \times \sqrt{\frac{100}{4}}$

= 10 m/s

Final velocity, v at equilibrium position, v = 5 m/s

Now, $\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$

A' = amplitude = 1.4142 m

b). $T=2 \pi \sqrt{\frac{m}{k}}$

m' = 2m

Hence, $T'=\sqrt2 T$

c). $\frac{\frac{1}{2}(4+4)5^2 + \frac{1}{2}\times 4 \times 10^2}{\frac{1}{2} \times 4 \times 10^2}$

$=\frac{1}{2}$

Therefore, factor $=\frac{1}{2}$

Thus, the energy will change half times as the result of the collision.

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2 years ago

Why do you see objects when you shine a flashlight in a dark room?​

Why do you see objects when you shine a flashlight in a dark room?