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ohaa [14]
3 years ago
6

Why do you see objects when you shine a flashlight in a dark room?​

Physics
1 answer:
anzhelika [568]3 years ago
8 0

Explanation:

We see objects in a dark room due to the emission of light photons which are sensitive to our eyes.

Darkness is simply a terminology used to describe the absence of light. Visible light to human is a component of the electromagnetic spectrum. Our eyes have receptors that picks the photons which light releases.

The particles of light are called photons.

  • When a torch is shines. It produces light due to emission of light by excitation of the metal in the bulb.
  • The light is in form of photons that spreads and travels in all direction in a room.
  • When they impinge on other bodies, they cause them to excite and release their own photons
  • Photons from the different parts helps to depict an object as it is.
  • The photo-receptors in our eyes picks up the photon and interprets it in our visual faculty.

learn more:

light waves brainly.com/question/8032392

#learnwithBrainly

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A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid
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Answer:

u_{s}=0.56

Explanation:

For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force

F_{s.max}=\frac{mv^2}{r} \\

Where the r is the radius of merry-go-round and v is the tangential speed

but

F_{s.max}=u_{s}F_{N}=u_{s}mg

So we have

u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}

Substitute the given values

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u_{s}=\frac{4\pi^2 5.5m}{(9.8m/s^2)(6.3s)^2} \\u_{s}=0.56

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3 years ago
A 19kg block is being pulled with a constant horizontal force of 95 Newton’s while also experiencing a constant friction force o
yuradex [85]

Answer:

A

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The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo
emmainna [20.7K]

Answer:

x-component of force is  38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P =  12

magnitude of base = B = 5

using Pythagoras theorem

                        H= \sqrt{P^{2} + B^{2}}

                 H= \sqrt{12^{2} + 5^{2}}

            H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\

y-component of force is given given as:

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