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DanielleElmas [232]
3 years ago
10

Calculate the molecular weight of Aluminium hydroxide​

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Al(OH)3 = 26.98 + [(16×3) + (1.01×3)] = 26.98 + 51.03 = 78.01 and the unit will be g/mol

<h3><em>Al(OH)3 = 78.01 g/mol</em></h3>
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A force that pushes or pulls is known as
xeze [42]

Answer:

A force that pushes or pulls is known as Newton's third law of Motion.

Explanation:

Newton's Third Law of Motion. Newton's Third Law of Motion states that for each action, there's an equal and opposite reaction. What this suggests is that pushing on an object causes that object to keep off against you, the precise same amount, but within the other way.

7 0
3 years ago
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how much force is needed to move a brick with a mass of 345-kg a distance of 28m while doing 1008 j of work?
Travka [436]

    Work = (force) x (distance)

     1,008 J  =  (force) x (28 m)

Divide each side by 28m  :    (1,008 kg-m²/sec²) / (28 m)  =  force

                                           Force =  36 kg-m/s²  =  36 Newtons .
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It doesn't matter what that force accomplishes.
It could be moving a brick, lifting a fish, or pushing a little red wagon.
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in the direction of the 28 meters.
5 0
3 years ago
What is tranlsatory motion? Give two examples​
Aleksandr [31]

Answer:

The motion in which all particles of a body move through the same distance in the same time.

Examples: A car moving along the road

A ball rolling on the ground

6 0
3 years ago
what is the final potential if 4j of work done to move 2c of charge from a point having initial potential of 5
a_sh-v [17]

Answer:

It’s 1

Explanation:

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So Here

Potential difference =2J/2C

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thankyou : )

7 0
3 years ago
An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri
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Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is 13m/s^2.

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

s=ut+\frac{1}{2}at^2

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

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s=0+\frac{1}{2}\times13\times 25

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s = 162.5  m

Therefore, distance traveled is 162.5 m.

3 0
3 years ago
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