The specific gravity of the object’s material is 5.09.
<h3>To calculate the specific gravity of the object:</h3>
Weight difference = 9 - 7.2 = 1.8 N = Buoyant force of water
Buoyant Force in water(Fb) = density of water x g x volume of the body(Vb)
1.8 = 1000 x 9.81 x Vb
Vb = 1.8/9810 cubic meter
Now, in the air;
Weight of body = mg = 9 N
Mass of body,m = 9/9.81 Kg
So,
Density of body = m/ Vb
= 9/9.81 ÷ 1.8/9810
= 5094.44 kg per cubic meter
The specific gravity of body = density of body ÷ density of water
= 5094.44 ÷ 1000
= 5.09
Therefore, Specific gravity of body = 5.09
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Answer:
The answer is below
Explanation:
a) The change in energy is the difference between the final energy and the initial energy.
ΔE (energy change) = Ef (final energy) - Ei (initial energy)

The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.
b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.
The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.
If it makes 50 complete back-and-forth wiggles in 1 second, then its frequency is <em>50 Hz</em>.
Answer:
Speed, S = 0.5m/s
Explanation:
Given the following data;
Distance = 30 meters
Time = 1 minute = 60 seconds
To find the speed;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the equation;

Substituting into the above formula;

Speed, S = 0.5m/s