a man carries a hand bag by hanging on his hand and moves horizontally where the bag does not move up or down. What is the work
1 answer:
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Answer:
a) speed when Jack sees the pot : 12.92 meters per second
b) height difference 163.115 meters
Explanation:
First to calculate te initial speed we use the acceleration formula:
a= v1-v0/t
Acceleration being gravity's acceleration (9.8 m/s^2)
v1 being the speed when Jill sees the pot
v0 when Jack sees it
and t the time between
Solving for v0 it would be
v1 - a*t = v0
replacing
For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)
The formula is
replacing
The position of the object at time t =2.0 s is <u>6.4 m.</u>
Velocity vₓ of a body is the rate at which the position x of the object changes with time.
Therefore,
Write an equation for x.
Substitute the equation for vₓ =2t² in the integral.
Here, the constant of integration is C and it is determined by applying initial conditions.
When t =0, x = 1. 1m
Substitute 2.0s for t.
The position of the particle at t =2.0 s is <u>6.4m</u>