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Zarrin [17]
2 years ago
5

Somebody help me!! Why do you think it's called the International Space Station???

Physics
1 answer:
AysviL [449]2 years ago
3 0
Dude this is an opinion you re read what chapter you read in class and then formulate an opinion but if you REALLY cant form one just comment and ill answer for you

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If an object is rolling without slipping, how does its linear speed compare to its rotational speed? If an object is rolling wit
salantis [7]

Answer:

v = r\omega

Explanation:

If the object is rolling without slipping, every unit of rotated angle equals to a distance perimeter rotated.

Suppose the object complete 1 revolution within time t. The angular distance is 2π rad. Its angular velocity is 2π/t

The distance it covered is its circumference, which is 2πr, and so the speed is 2πr/t

So the linear speed compared to angular speed is

\frac{v}{\omega} = \frac{2\pi r/t}{2\pi /t} = r

v = r\omega

6 0
3 years ago
(01.01 LC) Two boxes are 8 cm apart. Which of the following should Janet do to
Trava [24]
Place the boxes 10cm apart, if they are closer that concentrates the mass of the boxes more
4 0
3 years ago
Read 2 more answers
What information should be posted on or near a dishwasher?
Murljashka [212]
A.. in case of any problems that may occur you would know what company to call
7 0
3 years ago
Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
bixtya [17]

Answer:

v = 0.99 c = 2.99 x 10⁸ m/s

Explanation:

From the special theory of relativity:

t = \frac{t_o}{\sqrt{1-\frac{v^2}{c^2} } }\\

where,

v = speed  of travel = ?

c = speed of light = 3 x 10⁸ m/s

t = time measured on earth = 90 years

t₀ = time measured in moving frame = 6 months = 0.5 year

Therefore,

90\ yr = \frac{0.5\ yr}{\sqrt{1-\frac{v^2}{c^2} } } \\\\\\\sqrt{1-\frac{v^2}{c^2}} =  \frac{0.5\ yr}{90\ yr}\\ 1-\frac{v^2}{c^2} = 0.00003086\\\frac{v^2}{c^2} = 1-0.00003086\\

<u>v = 0.99 c = 2.99 x 10⁸ m/s</u>

8 0
3 years ago
Responding to an alarm, a 765-N firefighter slides down a pole to the ground floor, 3.5 m below. The firefighter starts at rest
Afina-wow [57]

Answer:

Explanation:

Let acceleration of fall be a .

v² = u² + 2as

v = 3.8 m /s

u = 0

s = 3.5 m

3.8² = 0 + 2 x a x 3.5

a = 2.06 m /s²

Since this acceleration is less than g , an upward force is acting on the firefighter in the form of friction . Let this force be F . Let mass of the firefighter be m .

m = 765 / 9.8

= 78.06 kg

mg - F = ma

765 - F = 78.06 x 2.06

765 - F = 160.8

F = 604.2 N .

4 0
2 years ago
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