Horizontal distance covered by a projectile is X = Vix *T
where Vix is the initial horizontal component of velocity and T is time taken by the projectile
Vix = ViCos theta
In question they said that initial velocity and angle is same on earth and moon
so Vix would remains same
now let's see about time taken T
time taken to reach the highest point
Vfy = Viy +gt
at highest point vertical velocity become zero so Vfy =0
0 = Vi Sin theta + gt
t = Vi Sintheta /g
Total time taken to land will be twice of that
On earth
Te= 2t
Te = 2Sinθ/g
on moon g is one-sixth of g(earth)
Tm = 2Sinθ/(g/6)
Tm = 6(2Sinθ/g)
Tm = 6Te
so total time taken by the projectile on moon will be six times the time taken on earth
From first equation X = Vix*T
we can see that X will also be 6 times on moon than earth
so projectile will cover 6 times distance on moon than on earth
Answer:
Explanation:
In this case, since the charged particle moves in circular motion, the centripetal force is equivalent to the magnetic force.
Answer:
The change in momentum is 
Explanation:
From the question we are told that
The mass of the probe is 
The location of the prob at time t = 22.9 s is 
The momentum at time t = 22.9 s is 
The net force on the probe is 
Generally the change in momentum is mathematically represented as
The initial time is 22.6 s
The final time is 22.9 s
Substituting values
Wave speed = (frequency) x (wavelength)
= (266 /sec) x (1.3 meters)
= 345.8 meters/sec
