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3 years ago

Given the following lens combination:

Physics

2 answers:

natulia [17]3 years ago

7 0

Given:

Lens.........diameter ...fl#

eyepiece...2cm............5

objective...40cm........15

focal length of eyepiece = 2*5 = 10cm

focal length of objective = 40*15 = 600cm

magnification = FL obj / FL eyp = 600/10 = 60x

pickupchik [31]3 years ago

6 0

magnification = (40*15)/(2*5) = 60X

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A steel ball with mass m=5.21 g is moving horizontally with speed ????=412 m/s when it strikes a block of hardened steel with ma

docker41 [41]

Answer:

a) The speed of the block immediately after the collision is $v_{2f}=(0.289\±0.002)m/s$ .

b) The impulse exerted on the block is $p_{2}=(4.2772\±0.0296)kg*m/s$ .

Explanation:

a) As this is a perfectly elastic collision, we can use the formula $v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}+ (\frac{m_{2}-m_{1}}{m_{1}+m_{2}} )v_{2i}$ , due $v_{2i}=0m/s$ , we obtain $v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}$ . Then with the data that we know $m_{1}=5.21g=0.00521kg, m_{2}=14.8kg$ and $v_{1i}=412m/s$ , therefore $v_{2f}=(\frac{2(0.00521kg) }{0.00521kg+14.8kg} ) 412m/s=0.289m/s$ or $v_{2f}=(0.289\±0.002)m/s$ adding uncertainty.

b) Now that we know the speed we can use $p_{2}=m_{2}*v_{f2} =14.8kg*(0.289\±0.002)m/s=(4.2772\±0.0296)kg*m/s.$

8 0

4 years ago

A baseball has a momentum of 6.0 kg m/s south and a mass of 0.15 kg. What is the baseball’s velocity? Show work

kupik [55]

Momentum of an object is defined as product of mass and velocity

so it is given as

$P = m* v$

here it is given that

mass = 0.15 kg

momentum = 6 kg m/s

so by plug in values in the above equation

$6 = 0.15 * v$

$v = \frac{6}{0.15}$

$v = 40 m/s$

so its speed will be 40 m/s

6 0

4 years ago

What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall

andrey2020 [161]

Answer:

$D_{s}$ ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere $Is_{cm}$ = 2/5 M R²

Spherical shell $Ic_{cm}$ = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

I = $I_{cm}$ + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

D = 2R

Ic = $Ic_{cm}$ + M D²

Ic = 2/3 MR² + M (2R)²

Ic = M R² (2/3 + 4)

Ic = 14/3 M R²

The sphere

Is = $Is_{cm}$ + M [ $D_{s}$ ²

Is = Ic

2/5 MR² + M $D_{s}$ ² = 14/3 MR²

$D_{s}$ ² = R² (14/3 - 2/5)

$D_{s}$ = √ (R² (64/15)

$D_{s}$ = 2,066 R

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4 years ago

Blood cell : ____________ :: bacteria : _________________

DIA [1.3K]

Blood cell : Eukaryotic cell
and
Bacteria : Prokaryotic cell.

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3 years ago

What mass of water will fill a tank that is 100.0 cm long, 50.0 cm wide, and 30.0 cm high? Express the answer in grams.

horsena [70]

Since the density of water is 1g/cm^3, The mass of water needed to fill the tank is 150000 grams

5 0

4 years ago

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