Number of moles :
n = mass solute / molar mass
n = 20 / 18
n = 1.111 moles
Therefore:
Molarity = moles solute / volume
Molarity = 1.111 / 30 => 0.37 M
Answer:
A. Passive Transport is migration of a molecule from one side of the cell membrane to the other, from an area of high electrochemical potential to a region of lower electrochemical potential.
B. Diffusion is an individual molecule of a material moving from a high-concentration location to a low-concentration area over a semipermeable barrier
C. Osmosis is the movement of molecules of water through a cell's partly permeable membrane from a liquid with a large concentration of water molecules to a solution with a lower concentration of water molecules.
D. Facilitated Diffusion are molecules that diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers.
E. Active transport is the transport of molecules across a cell membrane against a concentration gradient from a low-concentration region to a high-concentration region.
F. Selectively permeable is when some chemicals or ions pass across the membrane, while others are blocked.
G. Cellular respiration are organisms mix oxygen with food molecules, directing the chemical energy in these substances into life-sustaining processes while eliminating carbon dioxide and water as waste material.
Explanation:
The correct answer is A.
B is incorrect because that only applies to nuclear fission.
C is incorrect because it only applies to nuclear fusion.
D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,
The final temperature, t₂ = 30.9 °C
<h3>Further explanation</h3>
Given
24.0 kJ of heat = 24,000 J
Mass of calorimeter = 1.3 kg = 1300 g
Cs = 3.41 J/g°C
t₁= 25.5 °C
Required
The final temperature, t₂
Solution
Q = m.Cs.Δt
Q out (combustion of compound) = Q in (calorimeter)
24,000 = 1300 x 3.41 x (t₂-25.5)
t₂ = 30.9 °C
