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3 years ago

The specific heat of beryllium is____ J/g°C

Chemistry

2 answers:

gregori [183]3 years ago

8 0

The specific heat of beryllium is 3) 1.83

BARSIC [14]3 years ago

7 0

The specific heat of beryllium is 3) 1.82

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26. A Grignard's reagent may be made by

Marat540 [252]

Its pretty easy, correct answer is D

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3 years ago

(answer is a period table element!) When apprehending a suspect, try not to put your ____ on him.

egoroff_w [7]

Answer:

Explanation:

try not to put your hands on him

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3 years ago

The diagram below shows the different phase transitions that occur in matter. Three bars are shown labeled Solid, Liquid, and Ga

Grace [21]

The arrow that will represent the phase change that involves the same amount of energy as arrow 1 will be arrow 4.

<h3>Phase change</h3>

Arrow 1 represents a phase change from liquid to gas while arrow 4 represents a phase change from gas to liquid.

In other words, arrow 1 and arrow 4 are direct opposites of one another,

This means that if X amount of energy is required for arrow 1, the same amount of energy will be needed for arrow 4 but in the reverse direction.

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2 years ago

Which statement best describes one way that plate tectonics causes change

Romashka-Z-Leto [24]

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2 years ago

200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio

Ede4ka [16]

Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

First we calculate how many moles of each reagent were added:

HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl

Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂

460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we calculate how many moles of Ba(OH)₂ reacted, by converting the total number of HCl moles to Ba(OH)₂ moles:

203.85 mmol HCl * $\frac{1mmolBa(OH)_{2}}{2mmolHCl}$ = 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we divide the number of OH⁻ moles by the total volume (100 mL + 200 mL):

716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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3 years ago