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2 years ago

The specific heat of beryllium is____ J/g°C

Chemistry

2 answers:

gregori [183]2 years ago

8 0

The specific heat of beryllium is 3) 1.83

BARSIC [14]2 years ago

7 0

The specific heat of beryllium is 3) 1.82

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If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Mamont248 [21]

Answer:

17.3 g

Explanation:

Given the following data;

Quantity of heat, Q = 0.507 J
Temperature = 0.007°C
Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

$Q = MCT$

Where;

Q represents the heat capacity or quantity of heat.
M represents the mass of an object.
C represents the specific heat capacity of water.
T represents the temperature.

Making "M" the subject of formula, we have;

$M = \frac {Q}{CT}$

Substituting the values into the formula, we have;

$M = \frac {0.507}{4.2*0.007}$

$M = \frac {0.507}{0.0294}$

Mass, m = 17.3 grams

8 0

2 years ago

How many moles of oxygen will occupy a volume of 2.50 liters?

loris [4]

Data:
n (number of mols) = ?
V (volume) = 2.50 Liters
If:
1 L → 1000 g
2.50 L → y

y = 1000*2.50 = 2500 g

Therefore:
m (mass) = 2500 g

Now:
Molar Mass (MM) of oxygen = 16 g/mol

Formula:
$n = \frac{m}{MM}$

Solving:
$n = \frac{m}{MM}$
$n = \frac{2500\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol}$
$\boxed{\boxed{n = 156.25\:mols}}\end{array}}\qquad\quad\checkmark$

7 0

2 years ago

Differentiate between Mendeleev's Period law and Modern Periodic law

NeX [460]

<h2>see in the attachment hope it helps you</h2>

7 0

2 years ago

2. Which of the following statements about inertia is correct?

Rina8888 [55]

Answer:

Explanation:

i think

8 0

2 years ago

Read 2 more answers

Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?

xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed methyl vinyl ketone.

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed methyl vinyl ketone.

It can be written as

$CH_{2} O + CH_{3} COCH_{3}$ → $HOCH_{2} -CH_{2} -CO-CH_{3}$

When it will be heated then it gives methyl vinyl ketones.

$HOCH_{2} -CH_{2} -CO-CH_{3}$ → $CH_{2} =CH-CO-CH_{3}$

So, the pair of reactants will be formaldehyde and acetone

To know more about aldol condensation

brainly.com/question/9415260

#SPJ4

6 0

1 year ago