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Anon25 [30]
3 years ago
10

The specific heat of beryllium is____ J/g°C

Chemistry
2 answers:
gregori [183]3 years ago
8 0
The specific heat of beryllium is 3) 1.83
BARSIC [14]3 years ago
7 0
The specific heat of beryllium is 3) 1.82
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How many moles do you need to prepare 1.675 L of a 8.50 M NaOH solution? Round your answer to 2 decimal places.
vampirchik [111]

Answer:

0.20 mol's

Explanation:

1.675 L = 1.675 dm^3

moles = V/(conc):

moles = 1.675/(8.5)

moles = 0.1970... --> 0.20

7 0
3 years ago
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How many grams of aluminum are needed to react completely with 1.2 mol of FeO?
a_sh-v [17]

Answer:

5

Explanation:

all you do is the math expression

4 0
3 years ago
ClO(4)− Express your answer as a chemical formula.
Nimfa-mama [501]

ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

<h3>What is Perchlorate ion?</h3>

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has  32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

Read more about Perchlorate ion here brainly.com/question/16895150

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3 0
2 years ago
For the reaction 3ZnCO3 + 2H3PO4 —&gt; 3H2O + 3CO2, how many miles of zinc carbonate are required to produce 3.0 mil of Zn3(PO4)
drek231 [11]

Answer:

\boxed{ \text{9.0 mol of ZnCO$_{3}$}}

Explanation:

(a) Balanced equation

3ZnCO₃ + 2H₃PO₄  ⟶ Zn₃(PO₄)₂ + 3H₂O + 3CO₂

(b). Calculation

You want to convert moles of Zn₃(PO₄)₂  to moles of ZnCO₃

The molar ratio is 1 mol Zn₃(PO₄)₂:3 mol ZnCO₃  

\text{Moles of ZnCO$_{3}$} =\text{3.0 mol Zn$_{3}$(PO$_{4})_{2}$ } \times \dfrac{\text{3.0 mol ZnCO$_{3}$}}{\text{1 mol Zn$_{3}$(PO$_{4}$)$_{2}$}} \\\\\\= \text{9.0 mol ZnCO$_{3}$}

You need \boxed{ \textbf{9.0 mol of ZnCO$_{3}$}} to form 3.0 mol of Zn₃(PO₄)₂.

4 0
3 years ago
i have 5 moles of gas in a container with a volume of 45 liters and at a temperature of 210k , what is the pressure inside the c
liraira [26]

is there any answer choices

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3 years ago
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