Answer:
Ionic bond
Explanation:
Covalent bonds can only form between non-metals and copper is a metal so it would be an ionic bond.
Answer:
6.53g of K₂SO₄
Explanation:
Formula of the compound is K₂SO₄
Given parameters:
Volume of K₂SO₄ = 250mL = 250 x 10⁻³L
= 0.25L
Concentration of K₂SO₄ = 0.15M or 0. 15mol/L
Unknown:
Mass of K₂SO₄ =?
Methods:
We use the mole concept to solve this kind of problem.
>>First, we find the number of moles using the expression below:
Number of moles= concentration x volume
Solving for number of moles:
Number of moles = 0.25 x 01.5
= 0.0375mole
>>Secondly, we use the number of moles to find the mass of K₂SO₄ needed. This can be obtained using the expression below:
Mass(g) = number of moles x molar mass
Solving:
To find the molar mass of K₂SO₄, we must know the atomic mass of each element in the compound. This can be obtained using the periodic table.
For:
K = 39g
S = 32g
O = 16g
Molar mass of K₂SO₄ = (39x2) + 32 + (16x4)
= 78 +32 + 64
= 174g/mol
Using the expression:
Mass(g) = number of moles x molar mass
Mass of K₂SO₄ = 0.0375 x 174 = 6.53g
Answer:
No
Explanation:
Fortunately, in this scenario, you are not out of luck. Each of these components has a unique trait that would allow you to easily separate them. For starters, you can separate all of the Iron with a strong magnet since iron has a magnetic field while sand and salt do not. Next, you can separate the salt and sand by adding water since salt will dissolve in the water leaving only the sand which is not soluble. Once the sand is removed you would simply need to distill the water/salt mixture which would separate the salt from the water. Now you have all three components separated and can get your wish.
1. Last Answer Choice
2. I am not sure
3. 183/310=90/150 so the answer is 150 mm Hg
Explanation:
NH₄F+ AICI₃, → NH₄CI + AlF₃
NH,F: in ionic form
NH₄⁺ + F⁻ = NH₄F
AICI in ionic form:
Al³⁺ + Cl⁻ = AlCl₃
NH Cl in ionic form:
NH₄⁺ + Cl⁻ = NH₄Cl
Al F in ionic form:
Al³⁺ + F⁻ = AlF₃
NH₄F+ AICI₃, → NH₄CI + AlF₃
Now we have to balance the equation with respect to the atoms:
aNH₄F+ bAICI₃, → cNH₄CI + dAlF₃
for N: a = c
H: 4a = 4c
F: a = 3d
Cl: 3b = c
let a = 1
c = 1
b = 
d =
Therefore we can imply that:
a = 3, b = 1 , c = 3 and d = 1 if we multiply through by 3
3NH₄F+ AICI₃, → 3NH₄CI + AlF₃
Learn more:
Chemical equation brainly.com/question/2924195
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