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The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine

Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

Specific heat of liquid bromine (c): 0.226 J/g.K

Volume of bromine (V): 10.0 mL

Initial temperature: 25.00 °C

Final temperature: 27.30 °C

Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0

3 years ago

What is the name of Bel on the periodic table

rewona [7]

Answer:

Nobelium or Beryllium

4 0

3 years ago

When 3.00 g of Mg is ignited in 2.20 g of pure oxygen, what is the limiting reaction? What is the theoretical yield of MgO?

Ksivusya [100]

Cause do to Jalisa is

7 0

4 years ago

MARKING BRAINLIEST!

blagie [28]

Answer: B) Linda’s speed was slower than Meg’s speed

Explanation: Meg ran almost twice as fast as Linda since she took less time to finish the same amount of distance

8 0

3 years ago

f 65mL of sulfuric acid and 25mL of sodium hydroxide were mixed and the solution had a density of 1.01g/mL, what is the heat of

user100 [1]

The question is incomplete, here is the complete question:

If 65 mL of sulfuric acid and 25 mL of sodium hydroxide were mixed and the solution had a density of 1.01 g/mL, What is the heat of the calorimeter in kJ given the temperature change of the above equation is -5.5 K. You may assume the solution has a heat capacity of 4.180 J/gK. Express your final answer in kJ and with 2 decimal places

Answer: The heat of the calorimeter is 2.09 kJ

Explanation:

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.01 g/mL

Volume of solution = [65 + 25] mL = 90 mL

Putting values in above equation, we get:

$1.01g/mL=\frac{\text{Mass of solution}}{90mL}\\\\\text{Mass of solution}=(1.01g/mL\times 90mL)=90.9g$

To calculate the heat released by the reaction, we use the equation:

$q=mc\Delta T$

where,

q = heat released

m = mass of solution = 90.9 g

c = heat capacity of solution = 4.180 J/g.K

$\Delta T$ = change in temperature = -5.5 K

Putting values in above equation, we get:

$q=90.9g\times 4.180J/g.K\times (-5.5K)=-2089.8J=-2.09kJ$

Heat released by the solution will be equal to the heat absorbed by the calorimeter.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

Heat absorbed by the calorimeter = -(-2.09) = 2.09 kJ

Hence, the heat of the calorimeter is 2.09 kJ

8 0

4 years ago