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timama [110]
3 years ago
11

Eggs with tough protective shells developed to

Chemistry
2 answers:
pychu [463]3 years ago
8 0

The correct answer is option C.

Eggs with tough protective shells developed to prevent the embryo from drying out.

The hard shell of the egg is made of calcium carbonate and it protects the embryo from predators and from drying out. The egg shell is porous which allows air and moisture to pass through its pores.

White raven [17]3 years ago
6 0

Answer:  The correct answer is -C) Prevent the embryo from drying out.

The amniotic egg of birds and  reptiles is surrounded by an outer, tough, and protective shell, which protects the egg from any damage, predators, pathogens, and drying out.

The tough shell and extra embryonic membranes create a safe environment where an embryo can develop into a whole organism (with different organs like eyes ,ears, brain, kidney, heart).

Thus, option C) is the right answer.


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What kind of water is found in littoral zone of a lake?
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The littoral zone of a lake is the area closest to the shore. It has very little biological activity but includes a lot of oxygen. The water in the lake's littoral zone is freshwater, free of living organisms such as plants and fish.

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2 years ago
The teacher in item 10 also needs to order plastic tubing. If each of the 60 students need 750 mm of tubing, what length of tubi
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45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

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6 0
3 years ago
2Ag + H2S ? Ag2S + H2 Which statement is true about this chemical equation? A) Ag (silver) is oxidized and H (hydrogen) is reduc
nadezda [96]

Answer:

It is A).

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6 0
2 years ago
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I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
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