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2 years ago

What kind of water is found in littoral zone of a lake?

1 answer:

8 0

The littoral zone of a lake is the area closest to the shore. It has very little biological activity but includes a lot of oxygen. The water in the lake's littoral zone is freshwater, free of living organisms such as plants and fish.

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What 3 sub types of covergent plate boundaries?

Virty [35]

(1) Ocean to Continent
(2)Continent to Continent
(3)Ocean to Ocean
are the three sub types of convergent plate boundaries.

5 0

2 years ago

- What is the concentration of hydrogen ions if the pH is 12?

ELEN [110]

Answer:

1 x 10^-12 mol dm^-3

Explanation:

[H+] = 10 ^ -pH

Therefore, pH 12 = 1 x 10^-12 hydrogen ion concentration

4 0

3 years ago

Convert mass to moles for both reactants. (round to 2 significant figures.)

Maslowich

Answer:

Explanation:

Given parameters:

Mass of CuCl₂ = 2.50g

Mass of Al = 0.50g

Unknown:

Number of moles of CuCl₂ and Al = ?

Solution:

To solve this problem, we must understand that the number of moles is a fundamental property used in stoichiometry calculations.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of CuCl₂ = 63.6 + 2(35.5) = 134.5g/mole

Molar mass of Al = 26.98g/mole

Number of moles of CuCl₂ = $\frac{2.5}{134.5}$ = 0.019moles

Number of moles of Al = $\frac{0.5}{26.98}$ = 0.019moles

4 0

3 years ago

Read 2 more answers

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = $T_1=33.9^oC=33.9+273K=306.9 K$

Final temperature of the water = $T_2$

Specific heat capacity of water under these conditions = c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

$Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)$

$-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC$

The new temperature of the water bath 32.0°C.

5 0

3 years ago

If the farmer had weighed out 32.0 pounds of chicken eggs rather than kilograms what mass of quail eggs would he need to weigh o

Ira Lisetskai [31]

To have 35 pounds of quail eggs, he would need 14.5 kilograms
1 pound= .45 pounds

8 0

2 years ago