A because they all something I forgot but a
Answer:
-4
Step-by-step explanation:
Answer:
$94
Step-by-step explanation:
Let the price of a bowl, a pan and a dish be $b, $p and $d respectively.
14b +9p +12d= 135 -----(1)
10b +6p +8d= 88 -----(2)
Subtracting equation (1) with equation (2):
14b +9p +12d -(10b +6p +8d)= 135 -88
Expand:
14b +9p +12d -10b -6p -8d= 47
4b +3p +4d= 47
Multiply both sides by 2:
8b +6p +8d= 47(2)
8b +6p +8d= 94
Thus, the price of 8 bowls, 6 pans and 8 dishes is $94.
The solution to the problem is as follows:
<span>log(1/7000)
= log1 - log7000
= -log(7*10^3)
= -log7 + log10^3
= -log7 + 3
= 0.8451 + 3
</span>
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