Question

What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.600 m long and has a mass of 5.60 grams.
a. 234 Hz
b. 517 Hz
c. 312 Hz
d. 366 Hz
e. 295 Hz

Answer 1

Complete Question

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Answer:

Explanation:

From the question we are told that

    The tension is  $T = 440 \ N$

     The length of the wire is $l = 0.600 \ m$

     The mass is  $m = 5.60 \ g = 0.0056 \ kg$

Generally the frequency is mathematically represented as

            $f = \frac{1}{2l} * \sqrt{\frac{T}{\frac{m}{l} } }$

=>        $f = \frac{1}{2 * 0.600 } * \sqrt{\frac{440}{\frac{0.0056}{0.600} } }$

=>        $f = 181 \ Hz$