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Natali [406]
3 years ago
12

What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.

600 m long and has a mass of 5.60 grams.
a. 234 Hz
b. 517 Hz
c. 312 Hz
d. 366 Hz
e. 295 Hz
Physics
1 answer:
Rasek [7]3 years ago
4 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told that

    The tension is  T  =  440 \  N

     The length of the wire is l =  0.600 \  m

     The mass is  m  =  5.60 \ g = 0.0056 \  kg

Generally the frequency is mathematically represented as

            f  =  \frac{1}{2l}  *  \sqrt{\frac{T}{\frac{m}{l} } }

=>        f  =  \frac{1}{2 * 0.600 }  *  \sqrt{\frac{440}{\frac{0.0056}{0.600} } }

=>        f = 181 \ Hz

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