The percent ionization of the acid is 44.56%
<h3>How can we calculate the percent ionization of the acid?</h3>
To calculate the percent ionization of the acid we are using the formula,
The H⁺ ion concentration [H⁺] = C x,
where, we are given,
C= concentration of the acid.
=0.39 M
x= degree of dissociation of the acid.
And one more thing we are given that, the pH of the acid=0.76.
So from the above statement we can say that,
pH = - log [H⁺]
Or,0.76 = -log [H⁺]
Or, log [H⁺] = -0.76
Or, [H⁺] = antilog -0.76
Or,[H⁺]= 10^-0.76
Or,[H⁺]=0.1738.
Now from the above calculation we know, the H⁺ ion concentration= 0.1738 M.
Now we put the known values in the above equation,
[H+]= Cx
Or,0.1739= 0.39 x
Or, x= 0.4459
From the above calculation we can conclude that the percent Ionization of the acid= 0.4459 X 100= 44.59%≈45%
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