Answer:
LED bulb = 0.145 A
Incandescent bulb = 0.909 A
CFL bulb = 0.218 A
Explanation:
Given:
Power rating of LED bulb (P₁) = 16 W
Power rating of incandescent bulb (P₂) = 100 W
Power rating of CFL bulb (P₃) = 24 W
Terminal voltage across the circuit (V) = 110 V
We know that, power is related to terminal voltage and current drawn as:
![P=VI](https://tex.z-dn.net/?f=P%3DVI)
Express this in terms of 'I'. This gives,
![I=\frac{P}{V}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BP%7D%7BV%7D)
Now, calculate the current drawn in each bulb using their respective values.
For LED bulb, ![P_1=16\ W, V=110\ V](https://tex.z-dn.net/?f=P_1%3D16%5C%20W%2C%20V%3D110%5C%20V)
So, current drawn is given as:
![I_1=\frac{16\ W}{110\ V}=0.145\ A](https://tex.z-dn.net/?f=I_1%3D%5Cfrac%7B16%5C%20W%7D%7B110%5C%20V%7D%3D0.145%5C%20A)
For incandescent bulb, ![P_2=100\ W, V=110\ V](https://tex.z-dn.net/?f=P_2%3D100%5C%20W%2C%20V%3D110%5C%20V)
So, current drawn is given as:
![I_2=\frac{100\ W}{110\ V}=0.909\ A](https://tex.z-dn.net/?f=I_2%3D%5Cfrac%7B100%5C%20W%7D%7B110%5C%20V%7D%3D0.909%5C%20A)
For CFL bulb, ![P_3=24\ W, V=110\ V](https://tex.z-dn.net/?f=P_3%3D24%5C%20W%2C%20V%3D110%5C%20V)
So, current drawn is given as:
![I_3=\frac{24\ W}{110\ V}=0.218\ A](https://tex.z-dn.net/?f=I_3%3D%5Cfrac%7B24%5C%20W%7D%7B110%5C%20V%7D%3D0.218%5C%20A)
Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.