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sergey [27]
3 years ago
6

How many atoms are in something determines its?

Physics
1 answer:
Oksanka [162]3 years ago
7 0
Is there any choices?
You might be interested in
The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on
lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied (\Delta t):

I=F\Delta t

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

\Delta p = m \Delta v

where m is the mass and \Delta v is the change in velocity. Multiplying and dividing by \Delta t, we get

\Delta p = m \frac{\Delta v}{\Delta t} \Delta t

and since \frac{\Delta v}{\Delta t} is equal to the acceleration, a, we have

\Delta p = ma \Delta t

And since the product (ma) is equal to the force, we have

\Delta p = F \Delta t

which corresponds to the impulse.

5 0
3 years ago
A 80 ohms resistor, 0.2 H inductance and 0.1 mF capacitor are connected in series across a generator (60 Hz, V rms=120 V). Deter
qaws [65]

Answer:

Impedance = 93.75 ohms

Current = 1.81 A

Explanation:

Resistance = R = 80 ohms

Inductance = L = 0.2 H

Inductive reactance = XL = X_{L}= = ωL = (2πf) L

= 2 (3.14) (60)(0.2) = 75.398 Ohms

Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]

= 26.526 Ohms  

Impedance = Z = \sqrt{R^{2} + (X_{L} - X_{C})^{^{2}}} =

= \sqrt{8788.511} = 93.747 ohms  

Voltage = \sqrt{2} × 120 = 169.7056 V

Current = I = V ÷ R = (169.7056) ÷ 93,747 = 1.81 A

8 0
3 years ago
Gold has a density of 19300 kg/m³. Calculate the mass of 0.02 m³ of gold in kilograms.
hjlf

Answer:

Mass = 386 kg

Explanation:

<u><em>Density = Mass / Volume</em></u>

Mass = Density × Volume

Where D = 19300 kg/m³ , V = 0.02 m³

<em>Putting the given in the above formula</em>

Mass = 19300 × 0.02

Mass = 386 kg

7 0
2 years ago
Read 2 more answers
A bag weighing 20 N is pushed horizontally a distance of 35 m across a
topjm [15]

Answer:

350J

Explanation:

Given parameters:

Weight of bag  = 20N

Distance moved horizontally  = 35m

Force applied  = 10N

Unknown:

Work done on the bag  = ?

Solution:

Work done is the force applied to move a body through given distance.

  Work done  = Force applied x distance

So;

 Work done  = 10 x 35  = 350J

6 0
2 years ago
A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with
MAVERICK [17]
The second object, the one that had twice the force applied to it, would move twice as far, I believe.
3 0
3 years ago
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