1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlad [161]
3 years ago
8

Please help me

Physics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

Explanation:

Your question is quite confusing, particularly the information about microsecond = 0.5.

I'm going to ASSUME that you mean coefficient of static friction μs = 0.5

unfortunately typing a subscript "s" is very difficult and probably leads to such confusion.

I will also ASSUME that the block, and spring, and force vector are all horizontal.

If the force is slowly increased until the block slips, the spring will compress until the force on each end equals the maximum static friction force. As we are not concerned with the compression distance, only the force, we can ignore the spring constant information and simply find the maximum available static friction force.

F = μN

F = μmg

F = 0.5(4.0)(9.8)

F = 19.6 N

Not that it matters, but the spring will have extended or compressed 19.6/0.8 = 24.5 m, which is a very long and very light spring

gtnhenbr [62]3 years ago
4 0

Answer:

Catch these points g thanks

Explanation:

0.1

You might be interested in
What does the dashed line represent in this diagram?
lys-0071 [83]
Motor branch circuit
8 0
3 years ago
What color does the star alpha centauri appear to be?
myrzilka [38]
B.yellow-white is the answer.
3 0
3 years ago
Read 2 more answers
Why do concave lenses always form virtual images?
MaRussiya [10]
<span>A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). The image of an object is found to be upright and reduced in size.</span>
3 0
4 years ago
Read 2 more answers
“Active listening” means to _______________. a. be quiet when someone is speaking b. check your understanding of what someone sa
DIA [1.3K]

Answer:

All of the above is the correct answer!!!

Explanation:

mark me brainliest

4 0
2 years ago
A plane flies horizontally at an altitude of 3 km and passes directly over a tracking telescope on the ground. when the angle of
Lubov Fominskaja [6]
The solution is:tan(θ) = opp / adj tan(θ) = y/x xtan(θ) = y 
Find x:
x = y/tan(θ) 
So x = 3/tan(π/6) 
Perform implicit differentiation to get the equation:
dx/dt * tan(θ) + x * sec²(θ) * dθ/dt = dy/dt 
Since altitude remains the same, dy/dt = 0. Now... 
dx/dt * tan(π/6) + 3/tan(π/6) * sec²(π/4) * -π/4 = 0 
changing the equation, will give us:
dx/dt = [3/tan(π/6) * sec²(π/6) * π/4} / tan(π/6) ≈ 12.83 km/min 
3 0
4 years ago
Other questions:
  • Explain why lenses are used for particular applications. ( please write a long detailed answer )
    5·1 answer
  • Salma is riding her bicycle. She rides 25.6 kilometers in 4 hours. What is her speed?
    8·1 answer
  • What is the base number for the metric system of units? In other words, by what number do we multiply to move up in scale ? ____
    10·2 answers
  • an electric heater is heated at 250w the quantity of heat generated in 10 minutes will be........... what is its answer
    8·1 answer
  • A ball is thrown downward from the top of a 31.0 m tower with an initial speed of 10.0 m/s. Assuming negligible air resistance,
    14·1 answer
  • Anong mga katutubong pilipinong nanirahan sa kabundukan ng cordillera​
    8·2 answers
  • A 50-ohm resistor in a 0.5 Amp circuit produces how much voltage drop?​
    12·1 answer
  • PLEASE PLEASE PLEASE HELP ME!!!
    10·1 answer
  • While you are standing on your front porch, you decided to walk to the end of your driveway, 10 meters away, and back to your fr
    6·1 answer
  • A flea jumps straight up to a maximum height of 0.490 m . What is its initial velocity v0 as it leaves the ground?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!