Answer: There are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
Explanation:
Given: Mass of silver = 1.4 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of silver is 107.86 g/mol. Therefore, moles of silver are calculated as follows.

Thus, we can conclude that there are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
M (C2H6) = n × M = 4.6 × 30 = 13.8 g.
Mole percent of O2 = 10% = 0.1 moles
Mole percent of N2 = 10% = 0.1 moles
Mole percent of He = 80% = 0.8 moles
Molar Mass of O2 = (2 x 16) x 0.1 = 3.2
Molar Mass of N2 = (2 x 14) x 0.1 = 2.8
Molar Mass of He = 4 x 0.8 = 3.2
1. Molar Mass of the mixture = 3.2 + 2.8 + 3.2 = 9.2 grams
2. Since at constant volume density is proportional to mass, so the ratio of
mass will be the ratio of density.
Ratio = Molar Mass of the mixture / Molar Mass of O2 = 9.2 / 32 = 0.2875