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arlik [135]
3 years ago
14

Types of equipments that uses in crude oil distillation? ​

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

An oil water separator (OWS) is a piece of equipment used to separate oil and water mixtures into their separate components. There are many different types of oil-water separator

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A buffer is prepared by adding 18.0 g of sodium acetate (ch3coona to 510 ml of a 0.160 m acetic acid (ch3cooh solution. determin
Nutka1998 [239]
Given:

mass of sodium acetate = 18.0 grams
volume of acetic acid = 510 ml
concentration of acetic acid = 0.160 M

Solve for the ph of the buffer:

pH = pKa + log [salt]/[acid]

pKa of acetic acid = 4.76
M of sodium acetate = 82g/mol
pH = 4.76 + log [18g/82g/mol] / [0.160M*(510/1000)]
pH = 5.19


4 0
3 years ago
2 H2(g) + O2(g) → 2 H2O(g)
alexgriva [62]

Answer:

77 L of water can be made.

Explanation:

Molar mass of O_{2} = 32 g/mol

So, 55 g of O_{2} = \frac{55}{32} mol of  O_{2} = 1.72 mol of  O_{2}

As hydrogen is present in excess amount therefore  O_{2} is the limiting reagent.

According to balanced equation, 1 mol of  O_{2} produces 2 mol of H_{2}O.

So, 1.72 mol of O_{2} produce (2\times 1.72) mol of H_{2}O or 3.44 mol of H_{2}O.

Let's assume H_{2}O gas behaves ideally at STP.

Then, P_{H_{2}O}.V_{H_{2}O}=n_{H_{2}O}.R.T   , where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.

At STP, pressure is 1 atm and T is 273 K.

Here, n_{H_{2}O} = 3.44 mol and R = 0.0821 L.atm/(mol.K)

So, (1atm)\times V_{H_{2}O}=(3.44mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)

  \Rightarrow  V_{H_{2}O}=77L

Option (b) is correct.

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3 years ago
Gerry is looking at an unknown element. He knows it has 1 valence electron and is highly reactive with water. What group is the
SVEN [57.7K]

Answer:

Group 1

because they have just one valance electron, group 1 elements are very reactiv.

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Examine the following equations.
Zigmanuir [339]

Answer:

A and B

Explanation:

This is because there was emission of gamma (Y) radiations in both the reactions.

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