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n200080 [17]
3 years ago
7

Hi, anyone play ultimate Frisbee? I have to answer a question but I don't understand :c

Physics
1 answer:
yanalaym [24]3 years ago
6 0
Hi first on is last ans
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Asexual reproduction involves only one parent. The offspring of this type of reproduction have - F DNA identical to the DNA of t
Sedbober [7]

Answer:

DNA identical to the DNA of the parent

Explanation:

5 0
3 years ago
The number of electrons in a copper penny is approximately 10*10^23. How large would the force be on an object if it carried thi
slega [8]
The charge on the electron is 1.6x10^-19C. So, 10^24 of them will be a  charge of 1.6x10^5C, F = q1xq2/[(4pi epsilon nought)r^2]
3 0
3 years ago
Read 2 more answers
A plate drops onto a smooth floor and shatters into three pieces of equal mass.Two of the pieces go off with equal speeds v at r
Firlakuza [10]

Answer:

Speed of the this part is given as

v_3 = \sqrt2 v

Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate

Explanation:

As we know by the momentum conservation of the system

we will have

P_1 + P_2 + P_3 = P_i

here we know that

P_1 = P_2

the momentum of two parts are equal in magnitude but perpendicular to each other

so we will have

P_1 + P_2 = \sqrt{P^2 + P^2}

P_1 + P_2 = \sqrt2 mv

now from above equation we have

P_3 = -(P_1 + P_2)

mv_3 = -(\sqrt 2 mv)

v_3 = \sqrt2 v

Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate

6 0
3 years ago
What happens if the breakdown voltage is exceeded.
s2008m [1.1K]

Answer:

this may help

Explanation:

maybe it will cause the eletric cause a fire that will mean it will spread till the fire men should come

7 0
3 years ago
If T, = 40 N, find T, and the mass of the weight (W).
seraphim [82]

Answer:4kg

Explanation:

acceleration due to gravity(g)=10m/s^2

Weight(w)=40N

Weight=mass x g

40=mass x 10

Divide both sides by 10

Mass =40/10

Mass=4kg

5 0
3 years ago
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