Answer:
Molar concentration of HCl = 0.279 M
Explanation:
Given data:
Volume of NaOH = 31.00 mL ( 31/1000 = 0.031 L)
Molarity of NaOH = 0.0900 M
Volume of HCl = 10.00 mL (0.01 L)
Molar concentration of HCl = ?
Solution:
Chemical equation:
NaOH + HCl → NaCl + H₂O
Number of moles of NaOH:
Number of moles = Molarity × volume in L
Number of moles = 0.0900 mol/L × 0.031 L
Number of moles = 0.00279 mol
For one mole of HCl one mole of NaOH is required.
Number of moles of HCl = 0.00279 mol
Molar concentration of HCl = 0.00279 mol / 0.01 L
Molar concentration of HCl = 0.279 M