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n200080 [17]
3 years ago
10

A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector ????1,x=1.33 m and ????1,y=

−2.89 m in a lettuce garden to another location, with position vector ????2,x=3.07 m and ????2,y=−4.33 m, where the lettuce appears to be tastier (but really is not; this turtle cannot see very well). The excursion takes 327 s to complete. What are the components and the magnitude of the turtle's average velocity in meters per second?
Physics
1 answer:
zvonat [6]3 years ago
3 0

Answer:

v = 22.68 10⁻³ m / s

vₓ = 5.32 10⁻³ m / s ,     v_{y} = 22.08 10⁻³ m / s

Explanation:

Velocity is defined by

      v = Δs / Δt

let's calculate for each axis

X axis

     vₓ = (3.07 - 1.33) / 327

     vₓ = 5.32 10⁻³ m / s

Y axis

     v_{y} = (4.33 - (- 2.89)) / 327

     v_{y} = 22.08 10⁻³ m / s

the magnitude of the velocity can be calculated using the Pythagoras theorem

     v² = vₓ² + v_{y}²

      v = √ (vₓ² + v_{y}²)

       v = √ (5.32² + 22.05²) 10⁻³

       v = 22.68 10⁻³ m / s

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