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nikklg [1K]
3 years ago
5

The temperature of a piece of copper with a mass of 95.4g increases from 25 degrees Celsius to 48.0 degrees Celsius when the met

al absorbs 849 J of heat. What is the specific heat capacity of copper?
Chemistry
2 answers:
solong [7]3 years ago
8 0

Answer:

The answer is 3.87 J/gC

Taya2010 [7]3 years ago
3 0

Answer:

The answer is 3.87 J/g°C

Explanation:

Here is the equation we are going to use:

C=\frac{q}{mT}

C= specfic heat in J/g°C

q = heat in joules (J)

m = mass in grams (g)

T = change in temperature

Here is what is given:

q = 849 J

m = 95.4 g

T = 48.0 - 25.0 = 23°C

Find:

Specific heat capacity in J/g

The first thing we are going to do is plug everything into the equation:

C = \frac{849J}{(9.54g)(23degreesC)}

Then we are going to solve for C

C = \frac{849J}{219.42gC} = 3.87 J/gCelsius

Hope this helps!

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The answer is 14.22 mg / (mm^2)
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3 years ago
Which equation is used to help form the combined gas law?<br> eP, V, P, V, т.
alexdok [17]

Answer:

The combined gas law is formulated from PV/T =K.

Explanation:

The combined gas law comprises of Boyle's law, Charles's law and Gay lusaac's law. This laws were not discovered but simply put together considering other cases of ideal gas law. It states that if the amount of gas is left unchanged, the ratio between the pressure, volume, and temperature is constant.

7 0
3 years ago
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 Cm^{3}

First, find the Density of given substance.

Formula used :    

Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}

Now,put all the values in this formula, we get

Density=\frac{46.9 g}{3.5 Cm^{3} } = 13.4 g/Cm^{3}

So, we conclude that the density of given substance (13.4 g/Cm^{3}) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/Cm^{3} respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

3 0
3 years ago
Read 2 more answers
State 3 differences between a solution, suspension and colloid.​
Art [367]

Explanation:

solution 1) homogeneous

2) do not scatter light

3) cannot be separated by filtration

Colloids 1) heterogeneous

2) scatter light

3) cannot be separated by filtration

suspension 1) heterogeneous

2) may either scatter light or be opaque

3) can be separated by filtration

8 0
3 years ago
What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4
valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]=\sqrt{ 0.3*7.42x10^{-4}}

[OH-]=0.01

pH=14-(-log[OH-])

pH=12

5 0
3 years ago
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