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igor_vitrenko [27]
3 years ago
9

An object with more mass has more kinetic energy than an object with less

Physics
1 answer:
Ber [7]3 years ago
4 0

Explanation:

The kinetic energy of an object is given in terms of its mass and object as :

K=\dfrac{1}{2}mv^2

An object with more mass has more kinetic energy. An object with less  mass, if both objects are moving at the same speed, in opposite directions, will have less kinetic energy. The square of v will give positive number.

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2. A 1.54 kΩ resistor is connected to an AC voltage source with an rms voltage of 240 V.
svp [43]

(a) The maximum potential difference across the resistor is 339.41 V.

(b) The maximum current through the resistor is 0.23 A.

(c) The rms current through the resistor is 0.16 A.

(d)  The average power dissipated by the resistor is 38.4 W.

<h3>Maximum potential difference</h3>

Vrms = 0.7071V₀

where;

  • V₀ is peak voltage

V₀ = Vrms/0.7071

V₀ = 240/0.7071

V₀ = 339.41 V

<h3> rms current through the resistor </h3>

I(rms) = V(rms)/R

I(rms) = (240)/(1,540)

I(rms) = 0.16 A

<h3>maximum current through the resistor </h3>

I₀ = I(rms)/0.7071

I₀ = (0.16)/0.7071

I₀ = 0.23 A

<h3> Average power dissipated by the resistor</h3>

P = I(rms) x V(rms)

P = 0.16 x 240

P = 38.4 W

Learn more about maximum current here: brainly.com/question/14562756

#SPJ1

8 0
2 years ago
WHOEVER RESPONDS TO THIS FIRST WILL GET BRAINIEST!!!!!!
postnew [5]

Answer:

alright i responded

Explanation:

you didnt say i had to answer

6 0
3 years ago
Read 2 more answers
Figure shows three blocks that are being pulled along a smooth horizontal surface. The masses of the blocks
Eva8 [605]

Answer:

The pulling force F is 200 N

Explanation:

We note that the tension in a rope between two or three blocks is given by the relation;

Where we have;

m₁ → T₁ → m₂ → T₂ → m₃ → F

T_1 = \dfrac{m_1}{m_1 + m_2 + m_3} \times F

T_2 = \dfrac{m_1 + m_2}{m_1 + m_2 + m_3} \times F

m₁ = 2 kg

m₂ = 4 kg

m₃ = 4 kg

T₂ = 120 N

Therefore, by substitution, gives;

2 kg → T₁ → 4 kg → 120 N → 4 kg → F

120 \ N = \dfrac{2 \ kg + 4 \ kg}{2 \ kg+ 4 \ kg+ 4 \ kg} \times F = \dfrac{6 \ kg}{10 \ kg} \times F

F = 120 N × (10 kg)/(6 kg) = 200 N

The pulling force F = 200 N.

7 0
3 years ago
A skateboarder is accelerating forward. How would his acceleration change if he had more mass?
Bond [772]

Answer:

increasing more mass will decrease the acceleration of the skateboarder.

Explanation:

Newton's Second Law states whenever an unbalanced force is applied on an object, it produces an acceleration in the object in the direction of force. This acceleration is directly proportional to force by inversely proportional to mass.

a\ \alpha\ \frac{F}{m}

where,

F = Force

a = acceleration

m = mass

If we consider force applied on the skateboarder, then the acceleration is inversely proportional to mass, only.

a\ \alpha\ \frac{1}{m}<u></u>

<u>Therefore, increasing more mass will decrease the acceleration of the skateboarder.</u>

8 0
3 years ago
A 52-kg bike is moving along a smooth road at a constant velocity of 8.4 m/s. What is the net force acting on the bike
kirill [66]

Answer:

0 N

Explanation:

Net force = mass × acceleration

∑F = ma

The velocity is constant, so the acceleration is 0.  Therefore, the net force is 0.

3 0
3 years ago
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