Answer:
a)
two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign. both charges are positive(+) or Negative (-)
b)
both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C
Explanation:
Given that;
L = 0.26 m
k = 180 N/m
x = 0.039 m
a)
we know that two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign.
b)
Spring force F = kx
F = 180 × 0.039
F = 7.02 N
Now, Electrostatic force F = Keq²/r²
where r = L + x = ( 0.26 + 0.039 )
we know that proportionality constant in electrostatics equations Ke = 9×10⁹ kg⋅m3⋅s−2⋅C−2
so from the equation; F = Keq²/r²
Fr² = Keq²
q = √ ( Fr² / Ke )
we substitute
q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )
q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )
q = √ (0.627595 / 9×10⁹)
q = √(6.97 × 10⁻¹¹)
q = 8.35 × 10⁻⁶ C
Therefore both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C
I think it is d if not then im sorry
C) 60 mph
I hope this helps =)
For the temperature 321 K, the temperature is 118.13 degree Fahrenheit.
<u>Explanation:</u>
degree Fahrenheit = (K - 273.15) * (9/5) + 32
Fahrenheit is a thermodynamic temperature scale, where the freezing point of water is 32 degree Fahrenheit. Based upon the definitions of the Centigrade scale and the experimental evidence, the absolute zero is -273.15 degree Celsius.
degree Fahrenheit of 321 K = (321 - 273.15) * (1.8) + 32
= 118.13 degree Fahrenheit.
Answer:
Explanation:
According to ohm's law
The current flowing through the wire is directly proportional to the potential difference applied across its ends , provided the temperature and other physical conditions of the wire like stresses and strains remains constant .