Answer:
Guysi hate math answer this guy plsss ssss
Answer:
5.5 m/s
Explanation:
Assuming the bottle is initially stationary, we can write the law of conservation of momentum as follows:
where
is the mass of the ball
is the initial velocity of the ball
is the mass of the bottle
is the final velocity of the bottle
is the final velocity of the ball
Solving for ,
False....................................
Answer:
241.24m
Explanation:
The height at which the shell explodes will be at the maximum height. In projectile motion, maximum height formula is expressed as:
H = u²sin²θ/2g
u is the initial speed = 70m/s
θ the angle of launch = 75°
g is the acceleration due to gravity = 9.81m/s²
Substitute the values into the formula and get H
H = 70²(sin75°)/2(9.81)
H = 4900sin75°/19.62
H = 4900*0.9659/19.62
H = 4733.037/19.62
H = 241.24m
Hence the height at which the shell explodes is 241.24m
Vi = 2m/s
a= 4.5 m/s
d= 340 m
vf= ?
use this equation ... vf^2=vi<span>^2+2ad
you should get vf = 55.3
hope this helps </span>
