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PtichkaEL [24]
3 years ago
8

Calculate the radiation dosage (in grays) for a 63‑kg person who is exposed for 5.0 s to a 3.0 Ci source of beta radiation. Assu

me that 100% of the radiation is absorbed and that each beta particle has an energy of 1.5×10−13 J.
Physics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

1.32142x10^-3 Gy

Explanation:

Mass m = 63kg

Time t = 5.0s

Beta energy = 1.5x19^-13J

1 Ci = 3.7x10¹⁰

3.0Ci = 3x3.7x10¹⁰

= 11.1x10¹⁰decay/s

We have a total of 11.1x10¹⁰ beta particles produced per second

The question says there is 100% absorption

Et = (11.1x10¹⁰)x5x1.5x10^-13

= 0.08325

The radiation dose = Et/m

= 0.08325/63 kg

= 0.001321428J/kg

= 0.001321428 grays

Or 1.32142x10^-3 Gy

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Calculate the power required of a 60-kg person who climbs a tree 5 meters high in 10 seconds.
Alina [70]

Answer:

Explanation:

Power = Energy/time

-Don't have energy so I'm gonna solve for it

Gravitational Potential Energy = mass x gravity x height

= 60 kg x 9.8 m/s2 x 5m

= 2940 J

Power = Energy/time

=2940 J/10 s

= 294 W

3 0
2 years ago
In the design of wall and column forms, the two most important factors are which of the following? a. rate of placement of the c
Simora [160]

Answer:

c. length of the wall or column and the rate of placement of the concrete

Explanation:

when designing for wall and column form-works, it is of utmost important to know the length of the wall and the type of concrete placement to be used.

Concrete placement has methods and precaution to be taken when doing the  form work

if the concrete placement is manually (hand or funnel) the form work height should not be more than 1 m to enable easy compaction and vibration of concrete in the form.

Also, if the form work length is too long and it is not well reinforced, it tends to burg if the force apply during concrete placement or during vibration is much.  

5 0
3 years ago
which of the glass lenses above, when placed in air, will cause rays of light (parallel to the central axis) to converge?
777dan777 [17]

Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

Learn more about the convex lens here:

brainly.com/question/12847657

#SPJ4

3 0
1 year ago
A 20-gram bullet traveling at 250 m/s strikes a block of wood that weighs 2 kg. With what velocity will the block and bullet mov
Shkiper50 [21]

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

6 0
3 years ago
If the moon is a full moon tonight what will be the moon one week later waxing or waning
tatiyna

-- Starting from nothing (New Moon), the moon's shape grows ('waxes')
for half of the cycle, until it's full, and then it shrinks ('wanes') for the next
half of the cycle.

-- The moon's complete cycle of phases runs 29.53 days . . . roughly
four weeks.

-- So, beginning from New Moon, it spends about two weeks waxing until
it's full, and then another two weeks waning until it's all gone again.
 
-- After a Full Moon, the moon is waning for the next two weeks.  So it's
definitely <em>waning</em> at <em><u>one week</u></em> after Full.


5 0
3 years ago
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