The equation we can use here is:
v^2 = v0^2 + 2 a d
where v is final velocity, v0 is intial velocity, a is
acceleration and d is distance
14^2 = 8^2 + 2 a (44)
<span>a = 1.5 m/s^2</span>
The answer is C why because I know it is
Answer:
The spring constant = 9.25 N/m
Explanation:
The equation of an object attached to a spring that is oscillating is
T = 2π√(m/k)
Where T = period of the oscillation, m = mass of the object, k = spring constant.
Making k the subject of the equation,
k = 4π²m/T²......................... Equation 1
Note: Period(T) is the time taken to complete one oscillation
Given: T = t/10 = 9.0/10 = 0.9 s, m = 190 g = 0.19 kg.
Constant: π = 3.14
Substitute these values into equation 1.
k = 4(3.14)²(0.19)/0.9²
k = 7.4933/0.81
k = 9.25 N/m
Thus the spring constant = 9.25 N/m
Answer:
due to production of heat through friction
The correct answer for this question is 6m/s. I hope this helps.
