Answer:
7923.6 g of (NH₄)₂SO₄ can be produced by this reaction
Explanation:
The reaction is:
2NH₃ (aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
In this reaction ratio is 1:1.
As the ammonia is in excess, the limiting reagent is the sulfuric acid.
So 1 mol of sulfuric can produce 1 mol of sulfate
Then, 60 moles of sulfuric must produce 60 moles of sulfate.
We convert the moles to mass:
60 mol . 132.06 g / 1mol = 7923.6 g
Chloroplast are the food producers of the cell.
<u>1) determine which formula you are going to use.</u>
<u>2) list your information.</u>
P = 101.325 kPa
V = 3.57 L
n = ?
R = 8.314
T = 273.15 K
<u>3) rearrange your formula</u>
<u>4) solve.</u>
<em>n = 0.159 mol NH₃</em>
The given question is incomplete, the complete question is:
Calculate the free energy of formation of NaBr(s) given the following information: NaBr(s) → Na(s) + 1/2Br2(l), ΔG° = 349 kJ/mol
A) –309 kJ/mol
B) –329 kJ/mol
C) None of the above
D) –349 kJ/mol
E) –369 kJ/mol
Answer:
The correct answer is option D, that is, -349 kJ/mol.
Explanation:
Based on the given information, the reaction is:
NaBr (s) ⇔ Na (s) + 1/2 Br₂ (l), the ΔG° of the reaction given is 349 kJ per mole. In the given question, it is clearly mentioned that there is a need to determine the free energy of the formation of NaBr. Thus, there is a need to keep Na (s) and Br₂ (l) at the reactant side and NaBr (s) at the product side.
Therefore, there is a need to reverse the reaction and change the sign on ΔG.
Now the reaction will become,
Na (s) + 1/2 Br₂ (l) ⇔ NaBr (s), and the ΔG° will now become -349 kJ per mole. Hence, -349 kJ per mole is the free energy of the formation of NaBr (s).
The molarity of the ammonia solution is 1.38 M
<h3>Definition of molarity</h3>
Molarity is defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>Determination of the mole of NH₃</h3>
•Mass of NH₃ = 23.5 g
•Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
•Mole of NH₃ =?
Mole = mass / molar mass
Mole of NH₃ = 23.5 / 17
Mole of NH₃ = 1.38 mole
<h3>Determination of the molarity </h3>
•Mole of NH₃ = 1.38 mole
•Volume = 1 L
•Molarity of NH₃ =?
Molarity = mole / Volume
Molarity of NH₃ = 1.38 / 1
Molarity of NH₃ = 1.38 M
Learn more about molarity:
brainly.com/question/9468209
<h3 /><h3 />