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Vesna [10]
3 years ago
7

Which force acts as an object to move it from rest or a constant straight line motion

Physics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

The force is Inertia

Explanation:

The force that acts on an object to move it from rest or a constant straight line motion is known as Inertia.

In physics the above statement is governed by Newton's first law of motion which is also known as Law of Inertia.

This law states that, an object that is at rest will remain at rest and an object that is moving will continue to move in a straight line with constant speed, if and only if the net force acting on the object is zero.

This implies that, A stationary object will remain motionless if no force acts on it while a object with constant velocity will continue moving with constant velocity until a force acts on it (neglecting resistance from air and friction).

tankabanditka [31]3 years ago
7 0

Answer:

Inertia.

Explanation:

Inertia is the property of matter by which it remains at rest or in uniform motion in the same straight line unless acted upon by some external force or the resistance to change in velocity by an external force.

Inertia is the tendency for an object at rest to remain at rest, or for a moving object to remain in motion in a straight line with constant speed.

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Light that enters your eye strikes cells in the back of your eye<br> true<br> False
tamaranim1 [39]

Answer: True

Explanation: Light enters your eye through the lens which then hits the retina which is located in the back of your eye.

5 0
3 years ago
In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m
leonid [27]

The initial velocity used by the flea to jump straight upward is 3.1 m/s

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Acceleration due to gravity (g) = 9.8 m/s²
  • Maximum height (h) = 0.49 m
  • Final velocity (v) = 0 m/s (at maximum height)
  • Initial velocity (u) =?

<h3>How to determine the initial velocity</h3>

The initial velocity used by the flea to jump upward can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – (2 × 9.8 × 0.49)

0 = u² – 9.604

Collect like terms

u² = 0 + 9.604

u² = 9.604

Take the square root of both sides

u = √9.604

u = 3.1 m/s

Thus, the initial velocity is 3.1 m/s

Learn more about motion under gravity:

brainly.com/question/22719691

#SPJ1

4 0
2 years ago
A 0.22-caliber handgun fires a 28-g bullet at a velocity of 765 m/s. Calculate the de Broglie wavelength of the bullet.
ser-zykov [4K]

Answer:

de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m

Explanation:

Given;

mass of bullet, m = 28 g = 0.028 kg

velocity of the bullet, v = 765 m/s

de Broglie wavelength of the bullet is given by;

λ = h / mv

where;

λ is de Broglie wavelength of the bullet

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

λ = h / mv

λ = (6.626 x 10⁻³⁴ ) / (0.028 x 765)

λ = 3.093 x 10⁻³⁵ m

Therefore, de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m

8 0
3 years ago
Two trains start a journey at the same time 120 miles apart, travelling towards each other. The first train is travelling at 60
Ludmilka [50]

The space between them is shrinking at (60+40)= 100 mph. It started out being 120 miles. To shrink to zero will take

(120 miles) / (100 mph) = 1.2 hours

That's 1 hour and 12 minutes.

7 0
3 years ago
A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m
love history [14]

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m

So, the charges are 2.55 m apart.

5 0
3 years ago
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