Answer:
0.00000045 m is the wavelength of blue light in decimal
The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.
<h3>
Molecular mass of potassium carbonate</h3>
The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;
M = K₂CO₃
M = (39 x 2) + (12) + (16 x 3)
M = 138 g
mass of carbon in potassium carbonate, K₂CO₃ is = 12 g
The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;
138 g ------------ 12 g of carbon
2.25 g ------------ ?
= (2.25 x 12) / 138
= 0.196 g
Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.
Learn more about potassium carbonate here: brainly.com/question/27514966
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Answer:
9.12 * 10^20 photons
Explanation:
Given that;
E=n⋅h⋅ν
Where;
E= energy of the electromagnetic radiation
n = number of photons
h = Plank's constant
ν = frequency of electromagnetic radiation
Hence;
n = E/hν
n = 3.46 × 10 -19/6.6 * 10^-34 * 575 * 10^-9
n = 3.46 × 10 -19/3795 * 10^-43
n= 9.12 * 10^20 photons
Answer:
T₂ = 84.375 K
Explanation:
Given data:
Initial volume = 3.3 L
Initial pressure = 2000 torr
Initial temperature = 225 K
Final temperature = ?
Final volume = 2.75 L
Final pressure = 900 torr
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁ /P₁V₁
T₂ = 900 torr× 2.75 L× 225 K / 2000 torr×3.3 L
T₂ = 556875 K/ 6600
T₂ = 84.375 K
The answer is (A).
Hope this helps :).
