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sesenic [268]
3 years ago
11

What is the mass of a sample of iron that has had 300.0 j applied to it and heats up from 20.0 degrees Celsius to 40.0 degrees C

elsius.. the specific heat of iron is 0.46j/gC
Chemistry
1 answer:
yuradex [85]3 years ago
4 0

Answer:

The mass of a sample of iron that has had 300 J applied to it and heats up from 20 degrees Celsius to 40 degrees Celsius is 32.61 grams.

Explanation:

Calorimetry is the measurement and calculation of the measurement of heat changes exchanged by a body or a system produced in physical and chemical processes.

The sensible heat of a body is the amount of heat received or transferred by a body to produce a change in temperature but without a change in physical state.

The sensible heat in a constant pressure is calculated by:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c, and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial)

In this case:

  • Q= 300 J
  • c= 0.46 \frac{J}{g*C}
  • m= ?
  • Tfinal= 40 C
  • Tinitial= 20 C

Replacing:

300 J= 0.46 \frac{J}{g*C} * m* (40 - 20) C

Solving:

300 J= 0.46 \frac{J}{g*C} * m* 20 C

m=\frac{300 J}{0.46 \frac{J}{g*C} * 20 C}

m= 32.61 g

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2C 2 H 6 +7O 2 ***&gt;4CO 2 +6H 2 O if 7.0 g of C 2 H 6 react with 18 g of O 2 , how many grams of water will be produced
Alex787 [66]

Answer:

grams H₂O produced = 8.7 grams

Explanation:

Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)

               7g           18g                             ?g

Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water

Moles Reactants

moles C₂H₆ = 7g/30g/mol = 0.233mol

moles O₂ = 18g/32g/mol = 0.563mol

Limiting Reactant => (Test for Limiting Reactant)  Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.

moles C₂H₆/2 = 0.233/2 = 0.12

moles O₂/7 = 0.08

<u><em>Limiting Reactant is O₂</em></u>

Moles and Grams of H₂O:

Use Limiting Reactant moles (not division value) to calculate moles of H₂O.

moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield

grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O

3 0
3 years ago
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