The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:
-0.19 v for A
-0.85 v for B
To solve for the standard cell potential, examine the reaction and
the standard cell potential for this case is (-0.19- (-0.85)) v = -0.66 v<span />
Hey there!
This is not reversible.
We know that this is a chemical change because heat is released (it burned brightly) and it formed a new substance (white powder).
Chemical changes are usually not reversible.
Since this is a chemical change, then this is not reversible.
Hope this helps!
<h2>question:How many significant figures are in 100.3</h2>
Answer:4
Answer:
Explanation:
Step 1. Calculate the moles of C₁₂H₂₂O₁₁
Step 2. Calculate the mass of C₁₂H₂₂O₁₁
Answer:
In writing the electron configuration for nitrogen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for N goes in the 2s orbital. The remaining three electrons will go in the 2p orbital. Therefore the N electron configuration will be 1s22s22p3.
Explanation:
hope you get it right:)
