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enot [183]
3 years ago
15

Write the electronic configuration of calcium oxide ​

Chemistry
1 answer:
Nana76 [90]3 years ago
6 0

Answer:

The electron configuration for calcium is: 1s2 2s2 2p6 3s2 3p6 4s2. Since calcium is in the fourth row and the second column of the s-block on the periodic table of elements, its electron configuration ends in 4s2. Every lower orbital is filled, starting with the 1s orbital.

Explanation:hope this helps

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Which of the following is an adaptation that helps protect the animal?
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C ( Porcupines use there’s sharp quills to defend themselves from larger predators!)
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2 years ago
The ro– group is the nucleophile. think about which group in the alkyl halide (iodoethane) is the leaving group. keep in mind th
jonny [76]
When Nucleophile (Alkoxide) reacts with Alkyl Halide (Substrate), Ether (product) is formed with the elimination of Leaving group (Iodide in this case).

This is SN² a nucleophilic substitution reaction which takes place in primary alkyl halides. Reaction is given as, 

8 0
3 years ago
State which statement is a physical change or a chemical change:
Oliga [24]

Answer:

Physical change: A,C ,D, F, H, I

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4 0
3 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

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3 0
3 years ago
As part of your job you are asked to make 1 liter of a 0.5 molar sucrose solution. how much sucrose (c12h22o11) do you need? use
kakasveta [241]

Answer:-  171 g

Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.

We know that molarity is moles of solute per liter of solution.

If molarity and volume is given then, moles of solute is molarity times volume in liters.

moles of solute = molarity* liters of solution

moles of solute = 0.5*1 = 0.5 moles

To convert the moles to grams we multiply the moles by molar mass.

Molar mass of sucrose = 12(12) + 22(1) + 11(16)  

= 144 + 22 + 176

= 342 grams per mol

grams of sucrose required = moles * molar mass

grams of sucrose required = 0.5*342  = 171 g

So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.




6 0
3 years ago
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