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3 years ago

Item 4 Which conditions produce the smallest and largest ocean waves? Choose the two correct answers.

Physics

2 answers:

Darya [45]3 years ago

5 0

Answer:

strong winds that blow for a long time over a great distance

weak winds that blow for short periods of time with a short fetch

Explanation:

When the winds are weak and blow for short periods, we experience the smallest ocean waves but when there are strong winds over a longer duration, the largest ocean waves are seen. Therefore, the conditions to produce the smallest and largest ocean waves are strong winds that blow for a long time over a great distance and weak winds that blow for short periods of time with a short fetch.

Masja [62]3 years ago

5 0

Answer:

the answer is

strong winds that blow for a long time over a great distance

weak winds that blow for short periods of time with a short fetch

Explanation:

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if weight is the force of gravity on an object, then your weight can change if the force of gravity is different on a different

Lapatulllka [165]

Yes, your weight can change if the force of gravity is different on a different planet.

Like on the Moon because acceleration due to gravity is 1/6 that on the Earth, your weight on the Moon would be 1/6 the value on the Earth.

But note that you mass remains the same.

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3 years ago

A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences

Zanzabum

Answer:

1.79 T

Explanation:

Applying,

F = BILsin∅................ Equation 1

Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force

make B the subject of the equation

B = F/ILsin∅............. Equation 2

From the question,

Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)

Substitute these values into equation 2

B = 2.15/(30×0.04×sin90°)

B = 2.15/1.2

B = 1.79 T

Hence the average field strength is 1.79 T

8 0

3 years ago

Why doesn’t the skydiver stop in mid air when the force of gravity on his body is equal to the air drag pushing in the opposite

Aleksandr [31]

Answer:

The weight of the sky diver contributes to the force pushing him down.

Explanation:

8 0

3 years ago

Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t

lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

$\eta$ = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

$m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)$ ..............1

put here value and we get m

m = $\frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}$

solve it we get

m = 5.156 kg/s

so by energy balance equation

m $\psi$ 1 = m $\psi$ 2 + W(r,out)

W(r,out) = m( $\psi$ 1 - $\psi$ 2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = $m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)$

W(r,out) = W(a,out) - m.To.(s1-s2) ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

$\eta$ = $\frac{W(a,out)}{W(r,out)}$ ..............................3

put here value

$\eta$ = \frac{5}{5.81}

$\eta$ = 86.1 %

6 0

3 years ago

I AM TIMED !! 30 POINTS Which is the smallest possible particle of an element?

zimovet [89]

Answer:

atoms

Explanation:

they are the smallest

4 0

3 years ago

Read 2 more answers