The weight of the automobile is 17,533.6 N.
<h3>
Weight of the automobile</h3>
The weight of the automobile is calculated as follows;
P = F / A
F = (W/4)
P = (W/4) / A
P = W/4A
W = 4AP
where;
W = (4)(217 x 10⁻⁴ m²)(2.02 x 10⁵ Pa)
W = 17,533.6 N
Thus, the weight of the automobile is 17,533.6 N.
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A set of stars will appear at a different angle to us at different times of the year because of the Earth's orbit around the sun. As it orbits around the sun, the parallax of the stars change.
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This question is to be tackled using vectors. When we look at the Southwest direction, we know it lies exactly between the South and West directions, producing an angle of 45 degrees. When we take sin(45) and multiply it by the original force, we obtain the component towards West; that is:
60 * sin (45) = 42.4 Newtons
And cos(45) gives us the force towards the South direction; that is:
60 * cos(45) = 42.4 Newtons
This can also be checked by using the formula of the magnitude of a vector and squaring 42.4, adding it to the square of 42.4 and then taking the square root of the answer.
sqrt(42.4^2 + 42.4^2) = sqrt(3600) = 60
Answer:
a)8.59 m/s
b)-0.8818 m/s²
Explanation:
a) Given the van moved 40 m in 7.70 seconds to a final velocity of 1.80 m/s
Apply the equation for motion;
where
t=time the object moved
d=displacement of the object
Vi=initial velocity
Vf=final velocity
Given
t=7.70s
Vf=1.80 m/s
d=40m
Vi=?
Substitute values in equation
b)Acceleration is the rate of change in velocity
Apply the formula
Vf=Vi+at
where;
Vf=final velocity of object
Vi=Initial velocity of the object
a=acceleration
t=time the object moved
Substitute values in equation
Given;
Vf=1.80 m/s
Vi=8.59 m/s
t=7.70 s
a=?
Vf=Vi+at
1.80=8.59+7.70a
1.80-8.59=7.70a
-6.79=7.70a
-6.79/7.70=7.70a/7.70
-0.8818=a
The van was slowing down.