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3 years ago

The theory that the outer core of the Earth is

Physics

1 answer:

ELEN [110]3 years ago

4 0

Scientists can tell this by looking at seismic waves released by earthquakes. ( if you need me to elaborate more ask)

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The linear impulse delivered by the hit of a boxer is 202 N · s during the 0.244 s of contact. What is the magnitude of the aver

zlopas [31]

Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.

Mathematically it is given by the relation:

Impulse = Force $\times$ Time

According to the numerical values given in the question, I = 202 Ns and T = 0.244 s

So, Force F = $\frac{Impulse}{Time}$ = $\frac{202}{0.244}$ = 827.86 N

Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

7 0

3 years ago

An 80 g, 40 cm long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 15 g ball of clay trav

fiasKO [112]

Answer:

θ = 12.95º

Explanation:

For this exercise it is best to separate the process into two parts, one where they collide and another where the system moves altar the maximum height

Let's start by finding the speed of the bar plus clay ball system, using amount of momentum

The mass of the bar (M = 0.080 kg) and the mass of the clay ball (m = 0.015 kg) with speed (v₀ = 2.0 m / s)

Initial before the crash

p₀ = m v₀

Final after the crash before starting the movement

$p_{f}$ = (m + M) v

p₀ = $p_{f}$

m v₀ = (m + M) v

v = v₀ m / (m + M)

v = 2.0 0.015 / (0.015 +0.080)

v = 0.316 m / s

With this speed the clay plus bar system comes out, let's use the concept of conservation of mechanical energy

Lower

Em₀ = K = ½ (m + M) v²

Higher

$E_{mf}$ = U = (m + M) g y

Em₀ = $E_{mf}$

½ (m + M) v² = (m + M) g y

y = ½ v² / g

y = ½ 0.316² / 9.8

y = 0.00509 m

Let's look for the angle the height from the pivot point is

L = 0.40 / 2 = 0.20 cm

The distance that went up is

y = L - L cos θ

cos θ = (L-y) / L

θ = cos⁻¹ (L-y) / L

θ = cos⁻¹-1 ((0.20 - 0.00509) /0.20)

θ = 12.95º

4 0

3 years ago

If a ball is given an initial speed of 15 m/s on a horizontal, frictionless surface, how fast will the ball be rolling in 5 seco

iris [78.8K]

The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.

7 0

4 years ago

The density of a hippo is approximately 1030kg/m^3,so it sinks to the bottom of the freshwater lakes and rivers. A 1500kg hippo

hram777 [196]

Answer:

14,700 N

Explanation:

The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:

$W-N=0$ (1)