A body that's moving with a negative acceleration is said to be?

Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to

rosijanka [135]

The question is incomplete, the complete question is;

Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to be more acidic in aqueous solution than H2S , e.g. have a larger Ka.

Answer:

H2Se

Explanation:

The acidity and extent of acid dissociation (shown by Ka value) depends on the nature of the bond between hydrogen and the group 6A element.

If we compare the H-S bond and the H-Se bond, we will discover that the H-Se bond is longer, weaker and breaks more easily than the H-S bond. As a result of this, H2Se is more acidic than H2S.

5 0

3 years ago

Support a scientist doing and experiment in nuclear fusion starts out with twelve atoms how many atoms will most likely results

vlada-n [284]

What context do they ask you?

5 0

4 years ago

In another experiment, a 0.150 M BF4^-(aq) solution is prepared by dissolving NaBF4(s) in distilled water. The BF4^-(aq) ions in

Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

Thus, I disagree with the claim.

3 0

3 years ago

Methane, CH4, is a(n) saturated or unsaturated hydrocarbon

Burka [1]

It has only single bonds.So it is saturated

5 0

4 years ago

Read 2 more answers

Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria

Andre45 [30]

Let us first calculate the accepted value of sulfate using the molar mass of sodium sulfate.

The molar mass of sodium sulfate is 2 Na + S + 4 O = 2 (22.99) + 32.07 + 4 (16)

Molar mass of Sodium sulfate = 142.05

Molar mass of sulfate = S + 4 (O) = 32.07 + 4 (16) = 96.07

% of sulfate in sodium sulfate = (Molar mass of SO4 / Molar mass of Na2SO4) x 100

% of sulfate = (96.07/142.05) x 100

% of sulfate = 67.6%

Theoretical value for % Sulfate is 67.6%

Percent error is calculated as

Percent Error = $\left | \frac{Experimental - Theoretical}{Theoretical} \right |$

Let us calculate mean for student A.

Mean for student A = (68.6 + 66.2 + 67.1) / 3 = 201.9/3 = 67.3 %

% error for student A = $\left | \frac{67.3 - 67.6}{67.6} \right |$

% error for student A = 0.44%

Mean for student B = (66.7 +66.6 + 66.5)/3 = 199.8 /3 = 66.6 %

% error for student B = $\left | \frac{66.6 - 67.6}{67.6} \right |$

% error for student B = 1.48%

Accuracy is the closeness of experimental values to the true value. This is defined in terms of absolute and percent errors.

Since percent error for student A is lower, we can say that student A was more accurate.

The precision of the data depends on the closeness of experimental values to each other. We can see that experimental values for student B were close to each other.

Therefore we can say that student B was more precise.

8 0

4 years ago