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Nata [24]
2 years ago
11

Part A The first step to engineering is to define the problem. Write down the problem the students have to solve, and describe t

he challenges they will face when coming up with a solution.
WILL MARK BRAINLIEST!!​
Chemistry
2 answers:
Oduvanchick [21]2 years ago
5 0

Answer:

Students will have to use their brains to solve problems and challenges they will face to find a solution to cleaning up oil spills. Students will face failures after completing their solution, lots of research, and problems during the making of their solutions. What will work? What won't?

Explanation:

Hope this helps!

Elena L [17]2 years ago
3 0

Answer:

Engineering is all about solving problems using math, science, and technical knowledge. And engineers have solved a lot of problems in the world by designing and building various technologies. We have everything from machines that can breathe for you in hospitals to suspension bridges to computers we use every day. All of these things were once designed by engineers using the engineering design process.

Explanation:

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What chemical substance is formed when the oh and h is joined?
Nezavi [6.7K]
Water is formed when this happens
3 0
3 years ago
What is the wave speed if the wave length is 8 and the frequency is 20
PilotLPTM [1.2K]

Answer:

160m/s

Explanation:

To find V Use the following formula V= F*W

V= Velocity F= Frequency W= Wavelength

V=20*8

=160m/s

4 0
3 years ago
How many grams of KBr are required to make 350. mL of a 0.115 M KBr solution?
Vsevolod [243]
0.115 M means that 0.115 moles of KBr are contained in a volume of 1000 ml, therefore a volume of 350 ml will have (0.115 × 0.35) = 04025 moles
From the formula of molarity moles = molarity × volume in liters
1 mole of KBr is equivalent to 119 g
Therefore, the mass = 0.04025 ×  119  g = 4.79 g
6 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!
irina [24]

that's the answer I think

6 0
2 years ago
Read 2 more answers
How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant
schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

  • 1 g = 1,000 mg
  • The molar mass of Cu is 63.55 g/mol
  • When 1 mole of Cu is deposited, 2 moles of electrons circulate.
  • The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
  • 1 A = 1 C/s

The time  that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s

3 0
3 years ago
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