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Len [333]
3 years ago
8

(Please help I will give brainliest to whoever answers)Classify each of the following as either an element, compound, mechanical

mixture, solution, colloid or suspension
a. Gold
b. Kool-aid
c. Carbon dioxide
d. Tomato juice
e. Milk
f. Salad
Chemistry
2 answers:
bonufazy [111]3 years ago
7 0

Answer:

element:a,c

compound:f

mechanical mixture

solution:b

colloid:e

suspension:d

Explanation:

elixir [45]3 years ago
3 0

Answer:

I wrote the whole table...

Explanation:

concrete ------Mixture------- Heterogeneous

sugar + pure water -------- Mixture--------- Homogeneous

iron filings (Fe)-------- Pure Substance---------- Element

limestone (CaCO3)-------- Pure Substance-------- Compound

orange juice (w/pulp)------ Mixture---------- Heterogeneous

Pacific Ocean------------- Mixture------------ Heterogeneous

air inside a balloon--------- Mixture------------- Homogeneous

aluminum (Al)---------------- Pure Substance------------ Element

magnesium (Mg)------------- Pure Substance------------- Element

acetylene (C2H2)------------ Pure Substance----------- Compound

tap water in a glass----------- Mixture-------------- Homogeneous

soil-------------- Mixture----------- Heterogeneous

pure water (H2O)---------------- Pure Substance-------------- Compound

chromium (Cr)----------- Pure Substance--------------- Element

Chex mix------------------ Mixture--------------- Heterogeneous

salt + pure water --------- Mixture----------- Homogeneous

benzene (C6H6)----------- Pure Substance----------- Compound

muddy water---------------- Mixture------------- Heterogeneous

brass -------------Mixture----------------- Homogeneous

baking soda------------ Pure Substance--------------- Compound

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How much heat (in joules) is required to completely melt 10.00 g of ice starting at 0 oc?
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A19.0g sample of brass, which has a specific heat capacity of 0.375·J*g^−1°C−, is dropped into an insulated container containing
djverab [1.8K]

Answer:

The final temperature is 20.3 °C

Explanation:

Considering that:-

Heat gain by water = Heat lost by brass

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{brass}\times C_{brass}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{brass}\times C_{brass}\times (T_i-T_f)

For water:

Mass = 300.0 g

Initial temperature = 20.0 °C

Specific heat of water = 4.184 J/g°C

For brass:

Mass = 19.0 g

Initial temperature = 81.7 °C

Specific heat of water = 0.375 J/g°C

So,  

300.0\times 4.184\times (T_f-20.0)=19.0\times 0.375\times (81.7-T_f)

1255.2T_f-25104=582.1125-7.125T_f

1262.325T_f=25686.1125

T_f = 20.3\ ^0C

<u>Hence, the final temperature is 20.3 °C</u>

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