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vova2212 [387]
4 years ago
15

Does visible have more energy than infrared radiation?

Physics
1 answer:
Drupady [299]4 years ago
8 0
Yes, infrared has less energy than visible light
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A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funkn
AlekseyPX

Answer:

D)  11 N

Explanation:

F = mg

In the vertical

30 = m(9.8)

m = 3.06 kg

in the horizontal

F = ma

F(unknown) - 5 = 3.06(2.0)

F(unknown) = 11.12... N

5 0
3 years ago
A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Ad libitum [116K]

Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

5 0
2 years ago
A bus comes to rest by applying brakes in 10 second calculate the initial velocity of the bus and distance travelled during the
Rina8888 [55]
I dont know the answer to this question
7 0
3 years ago
An engine extracts 441.3kJ of heat from the burning of fuel each cycle, but rejects 259.8 kJ of heat (exhaust, friction,etc) dur
Lilit [14]

Answer:

  • The thermal efficiency is 0.4113.

Explanation:

We know that the thermal efficiency is the ratio of work done by the engine over the heat taken

\eta = \frac{W_{made}}{Q_{in}}

Now, how much work the engine do in a cycle?

We know that the work done in a cycle must be equal to the heat taken minus the heat rejected

W{made} = Q_{in} - Q_{rejected}

So, the thermal efficiency will be:

\eta = \frac{Q_{in} - Q_{rejected}}{Q_{in}}

\eta = \frac{Q_{in}}{Q_{in}} - \frac{Q_{rejected}}{Q_{in}}

\eta = 1 - \frac{Q_{rejected}}{Q_{in}}

Putting the values of the problem

\eta = 1 - \frac{259.8 kJ }{441.3kJ}

\eta = 0.4113

7 0
4 years ago
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t
Nataly [62]

Answer:

Explanation:

Given

N0 = 20kg (original substance)

decay constant λ = 0.179/sec

time t = 300s

We are to find N(t)

Using the formula;

n(t) = N0e^-λt

Substitute the given values

N(t) = 20e^-(0.179)(300)

N(t) = 20e^(-53.7)

N(t) = 20(4.7885)

N(t) =143.055

To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152

About 7 times the original material is still radioactive

4 0
3 years ago
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