Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
length of each rod is 1.1 m, while the mass of each is 0.11 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 8.3 mm. Determine the current in the rods.
1 answer:
Answer:
I = 215.76 A
Explanation:
The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.
Fm = u_o*I^2*L/2*π*d
where I is the current in each rod, d = 0.0082 m is the distance 27rId
between each, L = 0.85 m is the length of each rod.
Fm = 4π*10^-7*I^2*1.1/2*π*0.0083
The mass of each rod is m = 0.0276 kg
F_m = mg
4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8
I = 215.76 A
note:
mathematical calculation maybe wrong or having little bit error but the method is perfectly fine
You might be interested in
Answer:
L= 12 light years
Explanation:
for length dilation we use the formula
now calculating Lo
Lo = 12.5×365×24×3600×3×10^8
= 1.183×10^17 m
now putting the values of v and Lo in the above equation we get
= 1.136×10^17 m
L= m
so L= 12 light years
Good morning.
We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.
We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.