Which ocean borders the west coast of this United States

A mass of 0.273 kg is placed on an incline of 38.382 degrees. It is attached by a rope over a pulley to a mass of 0.254 kg. Find

Natali5045456 [20]

here tension in the string is counter balanced by weight of block of mass m1

so we can say

$T = m_1g$

$T = 0.254 \times 9.8 = 2.49 N$

now on the other side the block which is placed on the inclined plane

we can say that component of weight of the block and friction force is counter balanced by tension force

$m_2g sin\theta + F_f = T$

now we can plug in all values to find the friction force

$0.273 \times 9.8 sin38.382 + F_f = 2.49$

$1.66 + F_f = 2.49$

$F_f = 0.83 N$

so it will have 0.83 N force on it due to friction

now to find the friction coefficient

$F_f = \mu \times F_n$

here we know that

$F_n = m_2gcos\theta$

$F_n = 0.273 \times 9.8 \times cos38.382 = 2.1 N$

now from above equation

$0.83 = \mu \times 2.1$

$\mu = 0.38$

so friction coefficient will be 0.38

8 0

3 years ago

If energy is continually added to a gas, what will it likely become?

tamaranim1 [39]

The gas will remain a gas and the energy will be transformed into heat raising the temperature
(Some very rare exceptions might occur)

5 0

3 years ago

A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m

love history [14]

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

$F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m$

So, the charges are 2.55 m apart.

5 0

3 years ago

Why dont we put (-ve) sign when calculating charge in electrostatics ?

Levart [38]

Answer:

The negative sign represents the flow of charge in an opposite direction relative to point of action.

5 0

3 years ago

In general, which type of planet would you expect to cause the largest doppler shift in the spectrum of its star?.

PilotLPTM [1.2K]

A giant (massive) planet close to the star is expected to cause the largest Doppler shift in the star's spectrum.

<h3>What is the Doppler Shift Method for Detecting Exoplanets?</h3>

Doppler spectroscopy is used to capture periodic velocity shifts in stellar spectra caused by orbiting giant planets. (This method is also known as the radial velocity method.)
The Doppler method, which is most commonly used to find exoplanets, is most suitable to look for very massive planets orbiting near their parent stars

<h3>What does the Doppler method tell us about planets? </h3>

The Doppler shift data can tell us something about the mass of the planet and the shape of its orbit. Since the Doppler shift only knows how fast it approaches and moves away from Earth, it is not possible to determine the exact mass of the planet without knowing the inclination of its orbit. Doppler data give a lower bound on mass.

To learn more about Doppler shift visit:

brainly.com/question/29022708

#SPJ4

8 0

1 year ago