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2 years ago

9

A zoo had 12 large aquariums with fish. The number of fish in each aquarium is shown 37, 58, 62,36,42,71,56,58,69,66,47,68 what

is the range in the number of fish

1 answer:

SSSSS [86.1K]2 years ago

6 0

Answer:

35

Step-by-step explanation:

First, we will define range.

The difference between the highest and lowest values in a data is called range. To find the range, first the highest and lowest values are found from data, then the lowest value is subtracted from the highest value.

In the above data,

Highest Value=71

Lowest Value=36

Range=Highest value-lowest value

=71-36

=35

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Find the measure of the indicated angles below.Drag the points to show the measure of the four angles

horrorfan [7]

<h2>Answer</h2>

A. Angle E = 113°

B. x = 16°

<h2>Explain</h2>

<u>Number A</u>

92 + 70 + 85 + ? = 360

162 + 85 + ? = 360

247 + ? = 360

? = 360 - 247

? = 113°

<u>Number B</u>

108 + 84 + ( x + 30 ) + ( 2x + 18 ) = 360

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2 years ago

A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

$C = Children; S = Students; A = Adults$

For the capacity, we have:

$C + S + A = 329$

For the tickets sold, we have:

$5C + 7S + 12A = 2388$

Half as many as adults are children implies that:

$A = \frac{C}{2}$

Required

Solve for A, C and S

The equations to solve are:

$C + S + A = 329$ -- (1)

$5C + 7S + 12A = 2388$ -- (2)

$A = \frac{C}{2}$ -- (3)

Make C the subject in (3)

$C = 2A$

Substitute $C = 2A$ in (1) and (2)

$C + S + A = 329$ -- (1)

$2A + S + A = 329$

$3A + S = 329$

Make S the subject

$S = 329 - 3A$

$5C + 7S + 12A = 2388$ -- (2)

$5*2A + 7S + 12A = 2388$

$10A + 7S + 12A = 2388$

$7S + 22A = 2388$

Substitute $S = 329 - 3A$

$7(329 - 3A) + 22A = 2388$

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$A = 2388 - 2303$

$A = 85$

Recall that: $C = 2A$

$C = 2 * 85$

$C = 170$

Recall that: $S = 329 - 3A$

$S = 329 - 3 * 85$

$S = 329 - 255$

$S = 74$

Hence, the result is:

$C = 170$

$S = 74$

$A = 85$

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