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3 years ago

Heat always flows from a what place to a what place

Physics

2 answers:

Vera_Pavlovna [14]3 years ago

6 0

Answer:

Heat is always the transfer of energy from an object at a higher temperature to an object at a lower temperature.

Explanation:

yulyashka [42]3 years ago

5 0

Answer:

Heat flows from high temperature to low temperature

Explanation:

the answer also may vary it can also be the heat flows from a warmer to colder place

hope this helped!

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A 1.60 m tall person lifts a 2.10-kg book from the ground so it is 2.20 m above the ground. What is the potential energy of the

Viefleur [7K]

Answer:

Explanation:

Given

mass of book(m)=2.1 kg

height up to which book is lifted is (h)2.2 m

height of person $(h_0)1.6 m$

Potential energy of book relative to ground=mgh

$PE=2.1\times 9.8\times 2.2=45.276 J$

(b)PE w.r.t to person head =mg(h-h0)

$=2.1\times 9.8\times (2.2-1.6)=12.348 J$

work done by person in lifting box 2.2 m w.r.t floor

Word done =Potential Energy of box relative to floor=45.2 J

6 0

3 years ago

A railroad car of mass 2.50 3 104 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railro

ipn [44]

Answer:2.5 m/s

37.5KJ

Explanation:

Let $u_1, u_2 , v_f$ be the initial velocity of rail road car ,coupled cars & Final velocity of system respectively.

$m=2.50\times 10^{4}$

Conserving momentum

$mu_1+3mu_2=4mv_f$

$4m+6m=4mv_f$

$v_f=2.5 m/s$

Therefore Final velocity of system is 2.5m/s

(b)Mechanical Energy lost =Initial Kinetic Energy -Final Kinetic Energy

$Initial Kinetic Energy=\frac{1}{2}m\left ( 4^2\right )+\frac{1}{2}m\left ( 2^2\right )=14m J$

$Final Kinetic Energy=\frac{1}{2}4m\left ( 2.5^2\right )=12.5m J$

$Mechanical Energy lost=14m-12.5m=3.75\times 10^4=37.5 KJ$

4 0

3 years ago

Leyes de newton primera ley

Nadusha1986 [10]

Answer:

may I know which language

5 0

2 years ago

An 80-kg man is skating northward and happens to suddenly collide with a 20-kg boy who is ice skating toward the east. Immediate

Fantom [35]

Answer:

6.25 m/s

Explanation:

mass of man (m1) = 80 kg

mass of boy (m2) = 20 kg

mass of man and boy after collision (m12)= 20 + 80 = 100 kg

velocity of man and boy after collision (v) = 2.5 m/s

angle θ = 60 °

How fast was the boy moving just before the collision ?

From the diagram attached, the first image shows the man and the boys motion while the second diagram shows their motion rearranged to form a triangle. With the momentum of the man and the boy forming the sides of the triangle.
M₁₂ = total momentum after collision = m12 x v = 100 x 2.5 = 250
Mboy = momentum of the boy before collision = m2 x Velocity of boy
Mman = momentum of the man before collision = m1 x velocity of man
from the triangle, cos θ = $\frac{Mboy}{M₁₂}$

cos 60 = $\frac{Mboy}{250}$

Mboy = 250 x cos 60 = 125

recall that momentum of the boy (Mboy) also = m2 x Velocity of boy

therefore

125 = 20 x velocity of boy

velocity of boy = 125 / 20 = 6.25 m/s

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3 years ago

5. Кульки із сталі, чавуну, міді і латуні мають однакові розміри. Яка з них має

Oksanka [162]

Answer:

Sorry, I don't understand this language, sorry dear

4 0

2 years ago