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Alika [10]
3 years ago
11

Heat always flows from a what place to a what place

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

Heat is always the transfer of energy from an object at a higher temperature to an object at a lower temperature.

Explanation:

yulyashka [42]3 years ago
5 0

Answer:

Heat flows from high temperature to low temperature

Explanation:

the answer also may vary it can also be the heat flows from a warmer to colder place

hope this helped!

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3. Imagine a 10kg block moving with a speed of 20m/s<br> calculate the kinetic energy of this block
MatroZZZ [7]
The formula of the kinetic energy is:
E_{k}  =  \frac{m v^{2} }{2}
where m is a mass of the object, v is speed of the object at the moment of time. So we have:
E_{k}  =  \frac{10* 20^{2} }{2}  = 2000J
The answer is 2000 Joules.
6 0
3 years ago
4 Suggest four ways in which participating in physical activities can build healthy relationship? 5.Show in two ways the influeb
valina [46]

Answer:

  • Increases levels of well-being neurotransmitters
  • Improves fitness
  • Improves mental health
  • Reduces the risk of developing diseases

Explanation:

Performing physical activities helps to build a healthy relationship with yourself, in the sense that physical activity promotes health at all levels. Health is a set of physical, mental and social well-being, so physical activity reaches all these levels and increases the quality of life for a person as a whole.

There are several types of physical activities that can be performed and you can choose the one that best fits your preferences and routine. A walk for example can be done in any safe place and at any time and it already helps in improving physical conditioning, in receiving serotonin and endorphins, in reducing blood pressure and protecting the heart and in improving mental health.

So the ideal is for each person to set their own goals in relation to their health and seek to achieve them, either to have a better quality of life, to socialize more with people, to prevent diseases, etc.

8 0
3 years ago
What is the relationship between inertia and mass?
ivann1987 [24]

Answer:

D

Explanation:

The greater the mass, the greater the inertia, and vice versa.

Remark: This means that a more massive object has a greater tendency to resist a change in its state of rest or motion.

8 0
3 years ago
Looking straight downward into a rain puddle whose surface is covered with a thin film of gasoline, you notice a swirling patter
Ivanshal [37]

Answer:

 

Explanation:

Point beneath you forms a beautiful iridescent green

refractive index of Gasoline n=1.38

Wavelength of Green light is \lambda =540\ nm

Here light first traverse from air(n=1) to gasoline , it reflects from  front surface of gasoline(n=1.38) so it suffers a phase change. After this light reflect from rear surface of gasoline and there is a decrease in refractive index(n=1.38 to n=1.33), so there is no phase change occurs .

For constructive interference

2t=(m+\frac{1}{2})\cdot \frac{\lambda }{n}

here t= thickness of gasoline film

n=refractive index

for m=0

t=\frac{\lambda }{4n}

t=\frac{540}{4\times 1.38}

t=97.82\approx 98\ nm                                                      

4 0
3 years ago
A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

f=12GHz=12\cdot 10^9 Hz is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

So the wavelength of the beam is

\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

y=\frac{m\lambda D}{a}

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m

and so, the diameter is

d=2y = 750 m

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

r=\frac{750 m}{2}=375 m

So the area is

A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2

And since the power is

P=100 kW = 1\cdot 10^5 W

The average intensity is

I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2

4 0
3 years ago
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