Answer:
The slowdown took 2.05 seconds and the roller coaster made a distance 20.5 during that time.
Explanation:
Start with the kinematic equation for velocity. Let v1 and v2 be the initial and the new velocity, respectively. Let s denote the distance made duringthe slowdown. Let m denote the mass of the roller coaster and "a" its acceleration (negative = deceleration). the equation is as follows:
Let us first determine the distance made:
The roller coaster made 20.5 meters during slowing down to 2 m/s. Now calculate the time this took.
It took 2.05 seconds to achieve the slowdown from 18 to 2 m/s
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Some Defined it by
"Supported by most but not all".
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Answer:
(a) upper : 3.18 m, lower: 2.58
(b) upper : 3180 mm, lower: 2580 mm
(c) upper : 2.81 m³, lower: 1.5 m³
Explanation:
given information:
the distance ranged from 43 to 53 cm
length of cylindrical pillar = 6 cubits
diameter = 1 cubit
(a) the cylinder's length in meters
upper = 53 cm x 6 cubits
= 318 cm
= 3.18 m
lower = 43 cm x 6 cubits
= 258 cm
= 2.58 m
(b) the cylinder's length in millimeters
upper = 3.18 m
= 3180 mm
lower = 2.58 m
= 2580 mm
(c) the cylinder's volume in cubic meters
upper : V = πr²l
= π (0.53m)² (3.18)
= 2.81 m³
lower : V = πr²l
= π (0.43m)² (2.58)
= 1.5 m³