All categories

3 years ago

Explain why the driver's reaction time affects the thinking distance.

Physics

1 answer:

Lemur [1.5K]3 years ago

7 0

Answer:

The thinking distance depends on the reaction time of the driver which could can affected by alcohol, distractions and tiredness. A faster speed increases both thinking distance, increasing the total stopping distance.

<h2><em>I hope this is helpful. Would appreciate if you add me as brainliest.</em></h2>

You might be interested in

A 115-turn circular coil of radius 2.71 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi

tester [92]

Answer:

80.6 mV

Explanation:

Parameters given:

Number of turns, N = 115

Radius of coil, r = 2.71 cm = 0.0271m

Time taken, t = 0.133s

Initial magnetic field, Bin = 50.1 mT = 0.0501 T

Final magnetic field, Bfin = 90.5 mT = 0.0905 T

Induces EMF is given as:

EMF = [(Bfin - Bin) * N * A] / t

EMF = [(0.0905 - 0.0501) * 115 * pi * 0.0271²] / 0.133

EMF = (0.0404 * 115 * 3.142 * 0.0007344) / 0.133

EMF = 0.0806 V = 80.6 mV

3 0

2 years ago

List 3 different things you can read off a motion graph.

Lunna [17]

Answer:

1) Position time graph

2) Acceleration time graph

3) Velocity time graph

6 0

2 years ago

Read 2 more answers

3. Waxing means "growing." Waning means

Sonja [21]

Answer:

I think it is the last one.

Explanation:

I am not sure because i am stuck on this one, too.

4 0

3 years ago

Read 2 more answers

Any four function of health post

lesantik [10]

Answer:

1. be the first line of treatment for minor health conditions

2.be the first line of assessment and decision making for further diagnosis and/or treatment and for referral to a higher level facility

3. be a center for all public health activities, such as outreach ...

4. provide basic health services to people who live in rural areas.

5 0

2 years ago

Calculate the change in the energy of an electron that moves from the n = 3 level to the n = 2 level. What type of light is emit

marissa [1.9K]

Answer:

Red light

Explanation:

The energy emitted during an electron transition in an atom of hydrogen is given by

$E=E_0 (\frac{1}{n_2^2}-\frac{1}{n_1^2})$

where

$E_0 = 13.6 eV$ is the energy of the lowest level

n1 and n2 are the numbers corresponding to the two levels

Here we have

n1 = 3

n2 = 2

So the energy of the emitted photon is

$E=(13.6) (\frac{1}{2^2}-\frac{1}{3^2})=1.9 eV$

Converting into Joules,

$E=(1.9 eV)(1.6\cdot 10^{-19} J/eV)=3.0\cdot 10^{-19} J$

And now we can find the wavelength of the emitted photon by using the equation

$E=\frac{hc}{\lambda}$

where h is the Planck constant and c is the speed of light. Solving for $\lambda$ ,

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{3.0\cdot 10^{-19}}=6.63\cdot 10^{-7} m = 663 nm$

And this wavelength corresponds to red light.

5 0

2 years ago