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enyata [817]
3 years ago
11

How many orbitals are in the second shell?a. 1b. 2c. 4d. 8

Chemistry
1 answer:
katrin2010 [14]3 years ago
3 0
The correct answer is C. 4

There are 4 orbitals in the second shell, and the number increases in further shells.
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Explanation: Answer A is correct because all plants, including grass, is a producer. Since there is an increase in grass eating animals (Antelope), more grass will be consumed, decreasing the amount of grass aka producer.

6 0
2 years ago
Practice Problems (show all work):
tekilochka [14]
1a 1
b 4
c 5
2 (5.44x10^2)(2.5x10^-3)(7.9x10^-3) = 1.1x10^-6
3 750/1000 = 0.750
4 50/0.5 = 100 mL
5 He came up with the modern ideals for chemsitty
6 0
3 years ago
A 25.0 ml sample of 0.723 m hclo4 is titrated with a 0.273 m koh solution. the h3o concentration after the addition of 50.0 ml o
3241004551 [841]
This is an acid base reaction and the chemical equation for the above reaction is as follows;
KOH  + HClO₄ ---> KClO₄ + H₂O
the stoichiometry of acid to base is 1:1
KOH is a strong base and HClO₄ is a strong acid therefore they both ionize completely into their respective ions
Number of KOH moles - 0.723 M/1000 mL/L x 25.0 mL = 0.018 mol
Number of HClO₄ moles - 0.273 M/1000 mL/L x 50 mL = 0.013 mol 
since acid and base react completely, 0.013 mol of acid reacts with 0.013 mol of base.
The excess base remaining is - 0.018 - 0.013 = 0.005 mol 
total volume of solution = 25.0 mL + 50.0 mL = 75.0 mL 
[OH⁻] = 0.005 mol/0.075 L = 0.067 M 
pOH = -log[OH⁻]
pOH = -log(0.067 M)
pOH = 1.17
pOH + pH = 14
Therefore pH = 14 - 1.17 = 12.83
by knowing pH we can calculate the [H₃O⁺]
pH = -log [H₃O⁺]
[H₃O⁺] = antilog[-12.83]
[H₃O⁺]= 1.47 x 10⁻¹³ M
5 0
2 years ago
What is transportation?
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3 0
3 years ago
Read 2 more answers
How many moles of CaO will be produced from 23.9 g of Ca?<br>2Ca(s) + O2(g) – 20:0(3)<br>mol​
inessss [21]

Answer:

0.6 moles of CaO will produced.

Explanation:

Given data:

Mass of calcium = 23.9 g

Moles of CaO produced = ?

Solution:

Chemical equation:

2Ca + O₂ → 2CaO

Number of moles of calcium:

Number of moles = mass/ molar mass

Number of moles = 23.9 g / 40 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of calcium and CaO.

            Ca         :          CaO

              2          :          2

            0.6         :        0.6

 0.6 moles of CaO will produced.

4 0
3 years ago
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