Fuel which has tremendous highest calorific value. (11 points if u answer this)

If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the

PolarNik [594]

Answer:

a. v₁ = 16.2 m/s

b. μ = 0.251

Explanation:

Given:

θ = 15 ° , r = 100 m , v₂ = 15.0 km / h

a.

To determine v₁ to take a 100 m radius curve banked at 15 °

tan θ = v₁² / r * g

v₁ = √ r * g * tan θ

v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s

b.

To determine μ friction needed for a frightened

v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg

v₂ = 4.2 m/s

fk = μ * m * g

a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²

a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²

F₁ = m * a₁ , F₂ = m * a₂

fk = F₁ - F₂ ⇒ μ * m * g = m * ( a₁ - a₂)

μ * g = a₁ - a₂ ⇒ μ = a₁ - a₂ / g

μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)

μ = 0.251

3 0

4 years ago

What is the formula for calculating density?

Sophie [7]

<span>Density can be determined by the mass of an object and how much it takes up space (volume). It is represented by the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass in kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of an object of 40.5kg and a volume of 15m^3. Find its density.</span>

D = M/V
D = (40.5 kg) / (15 m^3)
<span>D = 27/10 or 2.7 kg/m^3 </span>

6 0

4 years ago

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Helppppppppppppppppppppppppppppppppppppppppppppppp

marta [7]

Answer:

A

My logic:

Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Universe.

Hope this helps!

8 0

3 years ago

A box of books weighing 325N moves at a constant velocity across the floor when the box is pushed with a force of 425 N exerted

iragen [17]

Answer:The coefficient of kinetic friction is 0.61

Explanation:A state of constant velocity connotes an acceleration equal to zero {this is evident from Acceleration=(final velocity-initial velocity)/time}

Consequently,a balanced forces system is attained

Force of pulling

F(x)=F×cosα=425N×0.817=347N

is equivalent to the resistance force.

F=U(k)×(Fw+Fsinα)=U(k)×(325N+425N×0,576)=U(k)×570N

Note; U(k) is the coefficient of kinetic friction

Equating the two force components,

The coefficient of static friction ×570N= 347N

The coefficient of static friction = 347N/570N

The coefficient of static friction =0.61

Please note that the coefficient of static friction is dimensionless .

This is as a result of the same unit of forces whose division resulted in the determination of the coefficient of kinetic friction.

5 0

3 years ago

How can you identify the north/south pole in a magnet. Is there a north/south pole in a magnetic field and if so how do we ident

gulaghasi [49]

If you have 2 magnets and you try to attract them and they attract that means there opposite but if you have two magnets and you try to attract them and they repel that means they’re the same magnet

6 0

3 years ago

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