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NemiM [27]
3 years ago
10

Which of the following represents a relation that is not a function?

Mathematics
1 answer:
Doss [256]3 years ago
7 0
A function is for every input, there is 1 output
aka
x never repeats with a different y

A. x doesn't repeat, it's a function

B. -8 repeats with 34 and 40, this is not a funciton (this is the answer0

C. x doesn't repeat, it's a function

D. x doesn't repeat, it's a function



answer is B
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21x =7?<br> A. x=3<br> B. None of these <br> C. x=147<br> D. x=28
Varvara68 [4.7K]

Answer: B

Step-by-step explanation:

To isolate x, you divide both sides by 21

21x=7

\frac{21x}{21}=\frac{7}{21}

x = 7/21

Simplify by dividing both the numerator and denominator by 7

x = 1/3

Since, 1/3 is not an option, B is the correct answer

6 0
2 years ago
Find the product 9,361×7=
timofeeve [1]

Answer:

65,527

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5 0
3 years ago
1.5r – 3r + 8r + 2.5r​
Svetllana [295]

Answer:

9r

Step-by-step explanation:

5 0
3 years ago
Find domain and range -√x-5+10
inysia [295]
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)

But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
8 0
3 years ago
How do you do this question?
r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

s = 1/216 u^(³/₂)

Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

s = (145√145 − 1) / 216

5 0
3 years ago
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