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m_a_m_a [10]
2 years ago
8

A hydraulic lift raises 1140 kg car through a height of 2.4 m. What is the potential energy

Physics
1 answer:
Sladkaya [172]2 years ago
5 0
1140x9.8x2.4= 26,812.8 significant figures Make it 27,000
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A plant dying after being exposed to poison represents a physical change.
Sphinxa [80]

Answer:

False is the correct answer.

It is considered more of a chemical change because all of the cells inside the plant decompose (change chemicaly)

5 0
2 years ago
Read 2 more answers
A mass weighing 32 pounds stretches a spring 2 feet. Determine the amplitude and period of motion if the mass is initially relea
grandymaker [24]

A mass weighing 32 pounds stretches a spring 2 feet.

(a) Determine the amplitude and period of motion if the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 6 ft/s.

(b) How many complete cycles will the mass have completed at the end of 4 seconds?

Answer:

A = 1.803 ft

Period = \frac{\pi}{2} seconds

8 cycles

Explanation:

A mass weighing 32 pounds stretches a spring 2 feet;

it implies that the mass (m) = \frac{w}{g}

m= \frac{32}{32}

= 1 slug

Also from Hooke's Law

2 k = 32

k = \frac{32}{2}

k = 16 lb/ft

Using the function:

\frac{d^2x}{dt} = - 16x\\\frac{d^2x}{dt} + 16x =0

x(0) = -1        (because of the initial position being above the equilibrium position)

x(0) = -6          ( as a result of upward velocity)

NOW, we have:

x(t)=c_1cos4t+c_2sin4t\\x^{'}(t) = 4(-c_1sin4t+c_2cos4t)

However;

x(0) = -1 means

-1 =c_1\\c_1 = -1

x(0) =-6 also implies that:

-6 =4(c_2)\\c_2 = - \frac{6}{4}

c_2 = -\frac{3}{2}

Hence, x(t) =-cos4t-\frac{3}{2} sin 4t

A = \sqrt{C_1^2+C_2^2}

A = \sqrt{(-1)^2+(\frac{3}{2})^2 }

A=\sqrt{\frac{13}{4} }

A= \frac{1}{2}\sqrt{13}

A = 1.803 ft

Period can be calculated as follows:

= \frac{2 \pi}{4}

= \frac{\pi}{2} seconds

How many complete cycles will the mass have completed at the end of 4 seconds?

At the end of 4 seconds, we have:

x* \frac{\pi}{2} = 4 \pi

x \pi = 8 \pi

x=8 cycles

5 0
2 years ago
suppose 384g of steam originally at 100C is quickly cooled to produce liquid water at 31C. How much heat must be removed from th
dlinn [17]

Answer:

Q=977216.256\ J=977.216\ kJ

Explanation:

Given:

  • mass of  steam, m=384\ g
  • temperature of steam, T_{is}=100^{\circ}C
  • temperature of resultant water, T_{fw}=31^{\circ}C

We have,

  • latent heat of vapourization of water, L=2256\ J.g^{-1}
  • specific heat capacity of water, c=4.186\ J.g^{-1}

<em>When we cool the steam of 100°C then firstly it loses its latent heat to convert into water of 100°C and the further cools the water.</em>

<u>Now the heat removed from steam to achieve the final state of water:</u>

\rm Q=latent\ heat\ of\ vapourization+sensible\ heat\ of\ water

Q=m(L+c.\Delta T)

Q=384(2256+4.186\times (100-31))

Q=977216.256\ J=977.216\ kJ

3 0
3 years ago
what is the mechanical advantage of a crowbar when a worker uses 10N of force to pry open a window that has a resistance of 500N
Oksana_A [137]

Answer:

50

Explanation:

The mechanical advantage of a machine is given by

MA=\frac{F_{out}}{F_{in}}

where

F_{out} is the output force

F_{in} is the input force

For the crowbar in this problem,

F_{in}=10 N is the force in input applied by the worker

F_{out}=500 N is the force that the machine must apply in output to overcome the resistance of the window and to open it

Substituting into the equation, we find

MA=\frac{500}{10}=50

3 0
3 years ago
Read 2 more answers
HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (20pts)
anyanavicka [17]

Explanation:

potential energy =360800J

mass(m)=?

height (h)=25m

g=9.8m/s²

we have

potential energy =360800J

mgh=360800J

m×9.8×25=360800

m=360800/(9.8×25)=1472.653061kg

8 0
3 years ago
Read 2 more answers
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