Mass = 0.201kg
Energy = 15J
temperature change = 10C
Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)
we can rearrange this to make specific heat capacity the subject
c =
c =
c =7.46268657
To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as
Here,
q = Charge
t = Time
R = Resistance
C = Capacitance
When the charge reach its half value it has passed 10ms, then the equation is,
We know that RC is equal to the time constant, then
Therefore the time constant for the process is about 14ms
Melting freezing and boiling are molecular changes
Answer:
E = 12.9 kJ
Explanation:
Given that,
Mass of John, m = 55 kg
It is standing on the edge of a diving board which is at a height of 24 m.
We need to find his mechanical energy. The mechanical energy of John is equal to its potential energy such that,
E = mgh
E = 55 kg × 9.8 m/s² × 24
E = 12936 J
or
E = 12.9 kJ
So, his mechanical energy is equal to 12.9 kJ.
Answer:
Work input W = -200.39 KJ
Explanation:
From the question, we are given;
m = 1.15 kg
Constant temperature T1 = T2 = 27 + 273 = 300k
Since the temperature is constant, we can say that the process is isothermal
P1 = 111 KPa
P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa
Now what we want to calculate is W1-2
Mathematically, for isothermal process;
W1-2 = mRTlnP1/P2
where R can be obtained from table and it is equal to 0.287 KJ/kg.k
Hence;
W1-2 = (1.15)(0.287)(300)(ln 111/840)
W1-2 = 99.015 * -2.023871690525 = -200.39 KJ
Kindly note that the value of the work is negative because work is done on the system and not by the system
