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o-na [289]
3 years ago
9

I really need help with chemical equations and balanced chemical equations ......

Chemistry
1 answer:
SashulF [63]3 years ago
3 0
What do u need help with? I’m sure I can help you
A chemical equation has 2 sides: the reactives side and the products side
For a chemical equation to be balanced these two side must have the same number of atoms of each type, since in a chemical reaction mass must stay the same

Each symbol in either side will have a subscript. A subscript is the tiny number at the bottom of the symbol. If a symbol has no subscript then that indicate there’s only one atom of that type. However if it has, for example, a 4, then that indicates the are 4 atoms of that type. The thing is these subscripts cannot be changed...
Ex.
HgO —> Hg + O₂
Hg = 1 Hg = 1
O = 1 O = 2
This is an unbalanced equation because the is not oxigen on side that the other.
To balance it u must add a coefficient. This number goes before the whole group of symbols — You can not break apart a group to insert a coefficient in the middle. This number is multiplied by the subscript on each of the symbols in the group. You need to find the correct coefficient to multiply by the elements on both sides of the equation.
Note that this coefficient does no have to be the same on both sides
Answer:
2HgO —> 2Hg + O₂
Hg = 2 Hg = 2
O = 2 O = 2
Explanation:
To fix the oxigen we need to add a coefficient to the side that has less quantity. Because 2 x 1 = 2 (1 Is oxigen’s subscript) we place the 2 in front of the group HgO, But in doing so we damage the mercury, so we need to go to the other side to fix that so we place 2 in front of Hg.

If you need any more help, have some exercises I can further explain or have more doubt about this explanation then let me know and I will help you

Ps: I do recommend you first write the quantity of each atom for each side like I did. It makes it easier to visualize what you have to balance



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(5 points)
ExtremeBDS [4]

<u>Answer 2 :</u> The given electronic configuration for a neutral atom of phosphorous in its ground state is incorrect.

Explanation :

A neutral atom of phosphorous has 15 electrons.

The given electronic configuration is incorrect.

The reason is, According to Aufbau principle, the electrons will be first filled in the sub-shell having lower orbital energy. As from the given configuration, 3p sub-shell has lower orbital energy than 4s sub-shell. So, the electrons will be filled in 3p sub-shell first. Hence, the ground state electronic configuration of neutral atom of phosphorous is,

1s^22s^22p^63s^23p^3

<u>Answer 3 :</u>

Element                     Rubidium              Magnesium                Aluminium

Symbol                             Rb                         Mg                              Al

Group number                  1                             2                               13

Number of valence          1                             2                                3

electrons

The order of general reactivity on the basis of number of valence electrons.

Rb > Mg > Al

Reason : The reactivity is determined by the number of electrons present in the outermost shell that means the element which have 1 valence electron will be more reactive because they can easily lose electrons.

5 0
2 years ago
When naming a binary compound, what ending do you use to represent anions?
spin [16.1K]
I believe You replace the ending of the elements name with -ide. example: magnesium flourine should should be magnesium flouride. 
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2 years ago
A scientist triples the temperature of a gas at constant pressure. By what factor does the gas’s volume change?
laila [671]
Hey there,

A scientist triples the temperature of a gas at constant pressure. By what factor does the gas’s volume change?

I believe that  when the scientist triples the temperature of the gas at a certain and constant pressure, the factor of the gas volume would change most likely with the double amount of pressure that the scientist put in the first place.

~Jurgen
4 0
2 years ago
Read 2 more answers
what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield
earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

TiS+H_2O\rightarrow TiO+H_2S

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}

\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g

To calculate the percentage yield of titanium (II) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

5 0
3 years ago
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